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ankoles [38]
2 years ago
12

A principal is organizing a field trip for more than 300 students. She has already arranged the transportation for 220 students.

Each school bus has the capacity to transport 40 students. Which of the following inequalities could be used to solve for x, the number of school buses still needed to transport all of the students?
A. 40x - 220 > 300
B. 40x + 220 > 300
C. 40x > 520
D. 40x > 300
Mathematics
2 answers:
chubhunter [2.5K]2 years ago
6 0

Answer:

B is your answer llsls

Step-by-step explanation:

jejdjdhd

lina2011 [118]2 years ago
5 0
B..I can’t explain it tho cause I’m horrible at explaining
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What is 4/15 divided by 2/3?
BaLLatris [955]

Answer: 0.4 or 2/5

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2 years ago
In order to play in chess tournaments at the Marshall Club, Malik pays a fee to become a member. In addition, he pays a set rate
Keith_Richards [23]

Answer:

p = 22.50 + 15t

Step-by-step explanation:

For Malik :

Membership fee = m

Rate per tournament = t

After 4 tournaments :

m + 4t = 85 - - - (1)

After 7 tournaments :

m + 7t = 130 - - - (2)

Subtract 2 from 1

4t - 7t = 85 - 130

-3t = - 45

t = 45 / 3

t = 15

Put, t = 15 in (1)

m + 4(15) = 85

m + 60 = 85

m = 85 - 60

m = 25

Massai pays 10% less membership fee than Malik

Hence, Massai's membership fee:

(100 - 10)% * 25

0.9 * 25 = $22.50

Total price, p, Massai will pay to compete in t tournaments ;

Total price = membership fee + (rate per tournament * number of tournaments)

p = 22.50 + 15t

3 0
2 years ago
A 1.5-mm layer of paint is applied to one side of the following surface. Find the approximate volume of paint needed. Assume tha
Mariulka [41]

Answer:

V = 63π / 200  m^3

Step-by-step explanation:

Given:

- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:

                                 y = √(42*x - x^2)

- The surface is coated with paint with uniform layer thickness t = 1.5 mm

Find:

The volume of paint needed

Solution:

- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

- The derivative of the function f'(x) is as follows:

                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

- The square of derivative of f(x) is:

                            f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }

- Now use the surface area formula:

                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

- The Volume of the pain coating is:

                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

8 0
3 years ago
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Answer: the answer varies since the size are not the same

Step-by-step explanation:

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4 0
3 years ago
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