Which statement is not always true?(1) The product of two irrational numbers is irrational.
(2) The product of two rational numbers is rational.
(3) The sum of two rational numbers is rational.
(4) The sum of a rational number and an irrational number is irrational.
The statement that is not always true is the <span>sum of two rational numbers is rational. The answer is number 3.</span>
Answer:
Just to recap, an equation has no solution when it results in an incorrect "equation".
For example:
Equation: x+3 = x+4
Subtract x: 3 = 4???
But clearly, 3 is not equal to 4, so this equation has NO SOLUTION.
Now onto our problem:
13y+2-2y = 10y+3-y
11y+2 = 9y+3
2y=1
y=1/2
9(3y+7)-2 = 3(-9y+9)
27y+61 = -27y+27
54y = -34
y = -34/54
32.1y+3.1+2.4y-8.2=34.5y-5.1
34.5-5.1=34.5y-5.1
5.1=5.1
infinite solutions
5(2.2y+3.4) = 5(y-2)+6y
11y+17 = 11y-10
17 = -10??
That's not true, so the option "5(2.2y+3.4) = 5(y-2)+6y" has no solution.
Let me know if this helps
Answer:
B(6 , -11)
Step-by-step explanation:
(x-2 , y+3) = (4 , -8)
Compare the x & y co ordinates
x - 2 = 4 ; y + 3 = -8
x = 4 +2 ; y = -8 - 3
x = 6 ; y = -11
B(6 , -11)
Top triangle: if the know angle measures are 90 and 55 and there are a total of 180, 90 + 55 + a = 180. This means that angle a = 35°
Bottom triangle: if a is 35, the angle connected to it is 35 because they are vertical angles. The angles of this triangle are 35 + 120 + b = 180. Angle b = 25°
To find the intercepts, we can set the opposite variable equal to 0 and solve.
Let's find the x intercept first.
5x - 4(0) = -20
5x = -20
Divide both sides by 5.
x = -4
<h3>The x intercept is -4.</h3>
Now let's find the y intercept.
5(0) - 4y = -20
-4y = -20
Divide both sides by -4.
y = 5
<h3>The y intercept is 5.</h3>
