<h3>
Answer: x-3</h3>
Since p(3) = 0, this means x = 3 plugs into p(x) to get 0
We can write p(x) as p(x) = (x-3)q(x) where q(x) is some other polynomial that multiplies with (x-3) to lead to x^3-3x^2-x+3
Let's plug in x = 3 and see what happens
p(x) = (x-3)q(x)
p(3) = (3-3)q(3)
p(3) = 0*q(3)
p(3) = 0
No matter what the result of q(3) was, it doesn't matter because it multiplies with 0 to get 0.
The general rule is: if p(k) = 0, then x-k is a factor of p(x). This is a special case of the remainder theorem.
You are able to divide or mutiply both so let's divide. Divide each by four to get1/2. hope this helped.
Answer:
13/12 x²
Step-by-step explanation:
x / 12 x + x²
Rewrite
x / 12 x + x + x²
Write the division as fraction
1/12 x + x + x²
Calculate the product
1/12 x² + x²
calculate the sum
13/12 x²
42/2=21
So it becomes 21+x=36 but keep going.
Add 21 to 36 to get the x by itself
x=57
