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tino4ka555 [31]
3 years ago
10

What is the equation of the line, in general form, that passes through the point (1,1) and has a y-intercept of 2.

Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0

Answer:

<h2>x + y - 2 = 0</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept.

Put the given y-intercept b = 2 and the coordinates of the point (1, 1) to the equation:

1=1m+2            <em>subtract 2 from both sides</em>

-1=m\to m=-1

The equation of a line:

y=-1x+2\to y=-x+2

The general form of an equation of a line:

Ax+By+C=0

Convert:

y=-x+2          <em>add x to both sides</em>

x+y=2         <em>subtract 2 from both sides</em>

x+y-2=0

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On a coordinate grid, point A is located in the first quadrant. Point B is located at (negative 1 over 2, 2).

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What are you telling me? I would help, but can you type in answer choices if there is. That would be very helpful. I don't understand what is " A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 4 grid lines to the right of the y-axis and 1 grid line above the axis. Point B is plotted at 1 grid line to the left of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.

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Step-by-step explanation:

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