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SSSSS [86.1K]
3 years ago
14

If a positive integer is cubed, it equals 216. What is the value of the same integer if it is squared, instead of cubed

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

24√3^4 i hope this helps if its wrong, im sorry.

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Please help me answer this question!!! and explain bc im very stupid and my grades are low. 15 points
mariarad [96]

Answer:

17

Step-by-step explanation:

The top angle is 90 degrees, so I would assume that m<1 is 90 degrees.  Plugging this into the equation gives us 90 = 4y + 22.  Subtract 22 from both sides, and we get 68 = 4y.  Divide both sides by 4, and we get 17 = y.

6 0
3 years ago
2+2 so you can get 40 pts I need to just write 20 characters so... ndds8bdsudbsd8s shdds8sjd sudh89hd
Zanzabum

Answer:

2+2 is 4

Step-by-step explanation:

You can imagine 2 cookies and then you get 2 more which is 4.

4 0
3 years ago
Estimate the unit rate.<br> 283 students in 11 classes
Archy [21]

Answer:

So estimate.

Really depends on what needs to be estimated, the answer or the overall equation.
So doing the real one first.
283/11 = 25 8/11

You can’t have “part” of a student so rounding this you can go up since 8 is more then half of 11

So 26 students

If you were to round the overall equation then you’d get
280 / 10 which is 28 students per class

So two options.

5 0
2 years ago
Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .
anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

We need to begin with the definition of tangent:

tan (x) =\frac{sin(x)}{cos(x)}

So we can replace into our formula and we got:

tan(x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

We have the following identities useful for this case:

sin(a-b) = sin(a) cos(b) - sin(b) cos(a)

cos(a-b) = cos(a) cos(b) + sin (a) sin(b)

If we apply the identities into our equation (1) we got:

tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}   (2)

Now we can divide the numerator and denominato from expression (2) by \frac{1}{cos(x) cos(y)} and we got this:

tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}

And simplifying we got:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

And this identity is satisfied for all:

(x-y) \neq \frac{\pi}{2} +n\pi

8 0
3 years ago
A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive
Leya [2.2K]

If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.

Calculation for the Amount of IV

It is given that,

1L IV contains 60meq of kcal

⇒ 1000 mL of IV contains 60meq of kcal

⇒ 1 mL of IV will contain 60 / 1000 meq of kcal

As per the question,

The amount of IV infused in the patient = 400 mL

⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)

= 4 × 6

= 24 meq of kcal

Hence, the patient receives 24meq of kcal amount of IV.

Learn more about amount here:

brainly.com/question/4567186

#SPJ1

6 0
2 years ago
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