It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
So, First we will do the sum of the three given polynomials,
Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
Now, we can perform the subtraction,
∴ Required difference
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-4</u></em>
<em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>.</u></em>
Answer:c
Step-by-step explanation:
To solve the problem we will use this equation where,
d will be distance.
x is the speed of the plane without tailwind.
y is the speed of the wind affecting the plane.
Going to Philadelphia the speed of the plane affected by wind will be x-y=220 miles/hr
Coming back with a tailwind, the speed of the plane will be x+y= 280 miles/hr.
since time = distance / speed, t1 =d/220 and t2 = d/280
and since the total time traveled is 6.5hrs
d/220 + d/ 280 = 6.5hrs
d = 800.8 miles x 2 (back and forth trip) the answer is 1601.6 miles
Answer:
Y= 2/3x +(5/3)
Step-by-step explanation:
First, have to get Y alone on one side 3y=2x+5
Second, have to get read of the 3 with the Y so divide each side by three.
