The sum of three consecutive integers is - 126. What are the integers?

1 answer:

4 0

Let the three consecutive integers be x , x+1 ,x+2
Given, sum of three consecutive integers = -126
x +x+1+ x+2 = -126
3x +3 = -126
3x = -126 -3
3x = -129
x = -129/3
x = - 43
x +1 = -42
x +2 = -41

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l = w + 3cmp = 2l + 2w = 58cm 

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58

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l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:

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