Vfjhjo uihg nhkk yfi hgfu hhff
Answer:
a. 5%
b. 55%
c. 70%
Step-by-step explanation:
a. The probability of customer wanting both services (P(O&T)) is:
![P(O)+P(T)+P(O\&T) = 0.75\\P(O)+P(O\&T) =0.60\\P(T)+P(O\&T) = 0.20\\P(O)+P(T)+P(O\&T) -[P(O)+P(T)+2P(O\&T)]=0.75 -(0.60-0.20)\\P(O\&T)=0.05=5\%](https://tex.z-dn.net/?f=P%28O%29%2BP%28T%29%2BP%28O%5C%26T%29%20%3D%200.75%5C%5CP%28O%29%2BP%28O%5C%26T%29%20%3D0.60%5C%5CP%28T%29%2BP%28O%5C%26T%29%20%3D%200.20%5C%5CP%28O%29%2BP%28T%29%2BP%28O%5C%26T%29%20-%5BP%28O%29%2BP%28T%29%2B2P%28O%5C%26T%29%5D%3D0.75%20-%280.60-0.20%29%5C%5CP%28O%5C%26T%29%3D0.05%3D5%5C%25)
The probability is 5%
b. The probability that the customer will need an oil change, but not a tire rotation (P(O)) is :
The probability is 55%
c. The probability that the customer will want exactly one of these two services (P(O)+P(T)) is:
The probability is 70%
---------------------------------------
Formula
---------------------------------------
Volume = πr²h
---------------------------------------
Find Volume of one tank
---------------------------------------
Volume of 1 tank = πr²h
Volume of 1 tank = 3.14 x 6² x 12
Volume of 1 tank = 678.24 ft³
---------------------------------------
Find Volume of 5 tanks
---------------------------------------
Volume of 1 tank = 678.24
Volume of 5 tanks = 678.24 x 5
Volume of 5 tanks = 3391.2 ft³
---------------------------------------
Answer: 3391.2 ft³
---------------------------------------
Answer:
It is f(x) = -x^2 + 2x + 4.
Step-by-step explanation:
As it has a maximum the coefficents of x^2 will be negative.
f(x) = -x^2 + 2x + 4
The y-intercept occurs when x = 0 so
y-intercept = 0 + 0 + 4 = 4.
-
