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2 years ago

What is the surface area of the pyramid?

Mathematics

2 answers:

Valentin [98]2 years ago

7 0

Depends on the base length height and base width. What are they then I can help

oee [108]2 years ago

6 0

Multiply the base and height and divide it by 2

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The Clark family must pay $2,820 in property tax on their home this year. The house payment $752 per month. What is their paymen

Harlamova29_29 [7]

It's actually easier than it seems. if the tax is paid in equal payments every month and the total throughout a year (12 months) is $2,820, you have to find out how much they pay every month
so divide the total by the number of months
2,820/12=235
they pay $235 in taxes every month
to find out the total of the taxes and the house payment, just add the monthly tax and the monthly house payment.
235+752
and your answer is the sum

8 0

3 years ago

Read 2 more answers

If x2 = 20, what is the value of x?

ArbitrLikvidat [17]

The correct answer is the second option: plus or minus square root of 20
Hope this helped :)

3 0

2 years ago

Read 2 more answers

PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.

anygoal [31]

Option C: $x=0$ and $x=\frac{5}{2}$ are the solutions.

Explanation:

The equation is $\frac{x}{3} =\frac{x^{2} }{x+5}$

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, $x=0$ and $x=\frac{5}{2}$ are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute $x=0$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}$

Thus, both sides of the equation are equal.

Hence $x=0$ is a true solution.

Now, Let us substitute $x=\frac{5}{2}$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}$

Thus, both sides of the equation are equal.

Hence, $x=\frac{5}{2}$ is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0

3 years ago

One of the two solutions to the equation $5x^2 - 11x - 36 = 0$ is $x = 4$. What is the other solution?

Firdavs [7]

Following are the calculation to the given equation:

Given:

$\to 5x^2 - 11x - 36 = 0$

one solution:

$x=4$

To find:

other solution=?

Solution:

$\to 5x^2 - 11x - 36 = 0\\\\\to 5x^2 - (20-9)x - 36 = 0\\\\\to 5x^2 - 20x+9x - 36 = 0\\\\\to 5x(x - 4)+9(x - 4) = 0\\\\\to (x - 4) (5x+9) = 0\\\\\to x - 4=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5x+9 = 0\\\\\to x = 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5x = -9\\\\\to x = 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = \frac{-9}{5}\\$