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2 years ago

Which ordered pairs are in the solution set of the system of linear inequalities

Mathematics

2 answers:

dolphi86 [110]2 years ago

7 0

Answer:

Step-by-step explanation:

if im incorrect lmk!

belka [17]2 years ago

6 0

Im pretty sure the answer is c

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In order to solve the system of equations below, Harvey multiplies each equation by a constant to eliminate the x terms.

Karo-lina-s [1.5K]

Answer:

The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77

Step-by-step explanation:

Let's find out the constants to eliminate the x terms

7 x + 3 y = 5

2 x + 5 y = negative 11

Let's multiply the first equation by 2 and the second one by -7, this way:

2 * (7 x + 3 y = 5)

-7 * (2 x + 5 y = negative 11)

14x + 6y = 10

-14x - 35y = 77

The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77

5 0

3 years ago

Read 2 more answers

If 750 was 1, then 301 would be?

horrorfan [7]

Answer:

225750

Step-by-step explanation:

i hope it was correct

7 0

2 years ago

A small juice company spends $1200 per day on business expenses plus $1.10 per bottle of juice them make. They charge $2.50 for

Greeley [361]

Cost price per bottle of juice = $1.10
Selling price per bottle of juice = $2.50
Profit per bottle of juice = $2.50 - $1.10 = $ 1.40
Let B be the number of bottles needed to sell in one day in order to equal its daily costs.
$1200 = $1.40B
857.14285714285714 = B
858 = B (round off to the nearest bottle)

The company must sell 858 bottles of juice in one day in order to equal its daily cost.

Hope this helps! =)

5 0

3 years ago

The table shows the number of miles that a car travels and the gallons of gasoline it uses to go those distances.

PtichkaEL [24]

Answer:

4 -.-

Step-by-step explanation:

8 0

2 years ago

Prove that {(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago