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Tasya [4]
3 years ago
11

The linear equation y = mx + b contains the point (4, -2) and is perpendicular to the

Mathematics
1 answer:
xenn [34]3 years ago
7 0

A linear equation is represented as: y = mx + b.

The equation of the line is: y =3x - 14

First, we calculate the slope (m) of 6x + 18y = 11

Make y the subject

18y = -6x + 11

Divide by 18

y = -\frac{1}{3}x + \frac{11}{18}

In y = mx + b

m \to slope

So, the slope of y = -\frac{1}{3}x + \frac{11}{18} is:

m = -\frac 13

Since, the line is perpendicular to 6x + 18y = 11

The slope of the line is:

m_1 = -\frac{1}{m}

So, we have:

m_1 = -\frac{1}{-1/3}

m_1 = 3

The line passes through (4,-2).

So, the equation is:

y =m(x - x_1) + y_1

This gives:

y =3(x - 4) -2

y =3x - 12 -2

y =3x - 14

Hence, the linear equation is:

y =3x - 14

Read more about  at:

brainly.com/question/11897796

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