Answer:
<h2>181 440</h2>
Step-by-step explanation:
We have 9 choices for Choosing the first object
8 choices for Choosing the 2nd object
.
.
.
3 choices for Choosing the seventh object
Therefore if we want to choose7 objects without replacement from 9 objects we have : 9×8×7×6×5×4×3 = 181 440
Also ,we can calculate it this way :
9P7 = 181 440
Answer:
c - 7 < -18
Step-by-step explanation:
Seven subtracted from c : c - 7
c - 7 < -18
The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
Basically what you need to do is draw 4 congruent rectangles and 2 comgriemt squares (The six sides of a rectangular prism). The sum of the area of these six quadrilaterals should equal 96. This would be my thought process.
Step 1: Sketch a Rectangular Prism
Step 2: Make some educated guesses on some possible side measurements for the quadrilaterals that form the prism.
Step 3: Guess and Check until the amount equals 96.
So we can guess that the sides of the rectangle might equal 2 and 3 units.
This would be 6 for the area. Times 4 for each of the 4 Rectangles. (24) and add the area of the ends of the prism (2*2*2) which is 8 and you will get 32.
Since we are looking for a surface area of 96 and not 32, we can assume that a 3*2*2 prism is not what we need. So we can try again with other values.
Let's try 6*3*3. 6*3*4 for the four rectangles plus 3*3*2 for the ends.
