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Paha777 [63]
2 years ago
7

Perform the indicated operation and simplify the result. Leave your answer in factored form.

Mathematics
2 answers:
vladimir1956 [14]2 years ago
8 0

Answer:

\frac{x}{y} \frac{5x}{\frac{x^{2} -4}{\frac{8x}{x+2} } }\\\\=\frac{5x(x+2)}{8x(x^{2} -4)}\\\\=\frac{5(x+2)}{8(x+2)(x-2)}\\\\=\frac{5}{8(x-2)}\\\\=\frac{5}{8}.\frac{1}{x-2}

Step-by-step explanation:

olga2289 [7]2 years ago
3 0

Step-by-step explanation:

\frac{ \frac{5x}{ {x}^{2} - 4 } }{ \frac{8x}{x + 2} }  =  \frac{5x}{ {x}^{2} - 4 }  \times  \frac{x + 2}{8x}  =  \frac{5x + 10}{ {8x}^{2}  - 32}   \\

hope it helps:)

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Solve for a,b 2^a × 2^b=144 value of a+3b+2 is...<br><br>please solve it...urgent...​
Nadya [2.5K]

Answer:

its a simple for me

Step-by-step explanation:

2+144 i

4 0
3 years ago
Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude
nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

  • a < b+c

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

  • b < a+c

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

  • c < a+b

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

Learn more about TRIANGLE here brainly.com/question/2217700

#SPJ4

8 0
2 years ago
The perimeter of the polygon above is
Rama09 [41]

Answer:

80 cm

Step-by-step explanation:

5 points in a star, each point has a perimeter of 16,

16 x 5 = 80

or just legit add all the 8's

DONT FORGET TO INCLUDE THE UNITS

4 0
3 years ago
Read 2 more answers
Describe a real life multiplication situation for which an estimate makes sense
Drupady [299]
If you are trying to create a garden of potted plants, you would find out how much soil each pot needs/holds and multiply that by how many pots you plan to use. then you would go to the store for potting soil, which let’s say came in smaller packs and you need to purchase multiple. use multiplication estimation to estimate how many bags you’d need.
I know this is a dumb example...sorry this is one I remember from my fourth grade math teacher ahah
3 0
3 years ago
The weights of red delicious apples are approximately normally distributed with a mean of 9 Ounces and a standard deviation of 0
Simora [160]

Answer:

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

Step-by-step explanation:

Let X: weight of a red delicious apple, and B: the weight of the box and packing material.

The distribution that will represent W: the total weight of the packaged 5 randomly selected apples will be also normally distributed.

Applying the property of the mean: E(aX)=aE(X), the mean of W will be:

\mu_W=E(W)=E(5X+B)=5E(X)+E(B)=5*9+10=45+10=55

Applying the property of the variance: V(aX+b)=a^2V(X), the variance of W will be:

\sigma^2_W=V(W)=V(5X+B)=5^2V(X)+V(B)=25*0.75+0=18.75

The mean standard deviation of W will be the squared root of V(W):

\sigma_W=\sqrt{V(W)}=\sqrt{18.75}=4.33

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

3 0
3 years ago
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