All categories

3 years ago

You complete 40% of your homework problems before dinner. what fraction of the problems did you complete before dinner?

Mathematics

2 answers:

Doss [256]3 years ago

8 0

Answer:

2/5

Step-by-step explanation:

Rzqust [24]3 years ago

4 0

Answer:

40/100

Step-by-step explanation:

You might be interested in

X^3 • x^4 I need it

Eddi Din [679]

x^7 Multiply x^3 by x^4 by adding the exponents

3 0

3 years ago

Read 2 more answers

Work for 8/18 in a decimal

vlabodo [156]

The decimal for 8/18 is 0.44, you simplify 8/18 to 4/9, divide 4 by 9 for the decimal.

3 0

3 years ago

The time it takes to drive to Joliet is 6 hours more than half the time it takes to drive to Davenport. It takes 8 hours to driv

Molodets [167]

It takes 8 hours to drive to Joliet, and that's 6 hours more than half the time it takes to drive to Davenport. So, I did 8-6 which equals 2. So 2 hours is half the time it takes to get to Davenport, which means it takes 4 hours to get to Davenport.

6 0

3 years ago

Read 2 more answers

One sample has a mean of M= 6, and a second sample has a mean of M = 12. The two samples are combined into a single set of score

lakkis [162]

Answer:

a) 9

b) 10

c) 8

Step-by-step explanation:

We are given the following in he question:

Mean of sample A = 6

Mean of sample B = 12

Formula:

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$\dfrac{\displaystyle\sum x_a}{n_a} = 6\\\\\dfrac{\displaystyle\sum x_b}{n_b} = 12$

a) original samples have n = 4 scores

$\dfrac{\displaystyle\sum x_a}{4} = 6,\sum x_a = 24\\\\\dfrac{\displaystyle\sum x_b}{4} = 12,\sum x_b = 48\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{4+4}=\frac{24 + 48}{4 + 4} = 9$

b) first sample has n = 3 and the second sample has n = 6

$\dfrac{\displaystyle\sum x_a}{3} = 6,\sum x_a = 18\\\\\dfrac{\displaystyle\sum x_b}{6} = 12,\sum x_b = 72\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{3+6}=\frac{18+72}{3+6} = 10$

c) first sample has n = 6 and the second sample has n = 3

$\dfrac{\displaystyle\sum x_a}{6} = 6,\sum x_a = 36\\\\\dfrac{\displaystyle\sum x_b}{3} = 12,\sum x_b = 36\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{6+3}=\frac{36+36}{6+3} = 8$

7 0

3 years ago

A radio disc jockey has 8 songs on this upcoming hour's playlist: 2 are rock songs, 3 are reggae songs, and 3 are country songs.

zlopas [31]

1/8=0.125 because each turn he has a 1/4 chance of pulling the rock songs so you would multiply the 1/4 by 2/1

3 0

3 years ago