The total cost before books are printed is $1200 (the constant).
The change to the total cost is the x, which is a variable, and can change depending on the amount of books printed.
hope this helps
Responder:
2³
5⁴
10³
a^6
Explicação passo a passo:
Quando um certo valor é multiplicado repetidamente,
Por exemplo,
a * a * a * a = a⁴ (a multiplicado 4 vezes)
Por isso,
2 x 2 x 2 = 2³
5 x 5 x 5 x 5 = 5⁴
10 x 10 x 10 = 10³
a x a x a x a x a x a = a^6
Answer:
495 cm
Step-by-step explanation:
Remark
When you do the subtraction, whatever is left (the decimal part) is the length in cm when multiplied by 100.
Solution
Remaining rope = starting length - what was used.
Remaining rope = 6.15 - 1.2
Remaining rope = 4.95 meters
Answer
The remaining rope = 4.95 * 100 = 495 cm
Answer:
a
Step-by-step explanation:
Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
