If x>4, then the quantity x-3 inside the absolute value symbol is already positive. So, in this case, |x-3| => x-3, and x-3 is all you need to write.
Hey there!
The correct answer would be that there are no x-intercepts. When you look at the graph, the function does not appear to pass through the x axis.
Therefore, your function has no x-intercept.
Hope this helps! :)
Answer:
StartFraction 3 Over x EndFraction + StartFraction 4 Over x squared EndFraction
Step-by-step explanation:
15
(2 + 5) - (2 x -4) = 15
7 - -8
Minus a negative goes upwards.
15
