Na-m; use m=2; and n=8

Order these numbers from least to greatest. 4811 , 4.626 , 5.63 , 9320

scoundrel [369]

4.626,5.63,4811,9320.........

8 0

3 years ago

BRO PLS I HAVE TO PASS THIS (click for question) 20 POINTS!

Masja [62]

Answer:

D, E.

Step-by-step explanation:

Simplify the expression inside the parentheses:

$3(23 + 18) < 6a$

$3(41) < 6a$

Multiply:

$123 < 6a$

Substitute each value provided for a:

Opt A. 123 < 6(18) = 123 < 108. Incorrect option.

Opt B. 123 < 6(19) = 123 < 114. Incorrect option.

Opt C. 123 < 6(20) = 123 < 120. Incorrect option.

Opt D. 123 < 6(22) = 123 < 132. Correct option.

Opt E. 123 < 6(24) = 123 < 144. Correct option.

3 0

2 years ago

Provide a solution for the following equation: 3x + 2y=4

shtirl [24]

Answer:

One solution is to find x and y by doing the following:

Step-by-step explanation:

Let's solve for x.

3x+2y=4

Step 1: Add -2y to both sides.

3x+2y+−2y=4+−2y

3x=−2y+4

Step 2: Divide both sides by 3.

x=-2/3y+4/3

Lets solve for y.

3x+2y=4

Step 1: Add -3x to both sides.

3x+2y+−3x=4+−3x

2y=−3x+4

Step 2: Divide both sides by 2.

y= -3/2x+2

7 0

2 years ago

In remodeling a kitchen, a builder decides to place a splash-guard behind the sink consisting of eight 6-inch-square ceramic til

oksano4ka [1.4K]

Answer:

(a) 0.4242

(b) 0.0707

Step-by-step explanation:

The total number of ways of selecting 8 herbs from 12 is

$\binom{12}{8}=495$

(a) If 2 herbs are selected, then there are 8 - 2 = 6 herbs to be selected from 12 - 8 = 10. The number of ways of the selection is then

$\binom{10}{6}= 210$

Note that this is the number of ways that both are included. We would have multiplied by 2! if any of them were to be included.

The probability = $\dfrac{210}{495}=0.4242$

(b) If 5 herbs are selected, then there are 8 - 5 = 3 herbs to be selected from 12 - 5 = 7. The number of ways of the selection is then

$\binom{7}{3}= 35$

This is the number of ways that both are included. We would have multiplied by 5! if any of them were to be included. In that case, our probability will exceed 1; this implies that certainly, at least, one of them is included.

The probability = $\dfrac{35}{495}=0.0707$

6 0

2 years ago

Sherri saves nickels and dimes in a coin purse for her daughter. The total value of the coins in the purse is $0.95. The number

forsale [732]

I’m guessing that this is for systems of equations?
n - nickels
d - dimes

These are the equations you start off with.
n = 5d-2
0.95 = 0.10d+0.05n

Substitute the top equation for n into the variable n in the bottom equation.
0.95 = 0.10d+0.05(5d-2)

Solve for d.
0.95 = 0.10d+0.25d-0.10
1.05 = 0.35d
3 = d

Substitute d into the top equation and solve for n.
n = 5(3)-2
n = 15-3
n = 12

There are 3 dimes and 12 nickels in the coin purse! Hope this helped <3

7 0

2 years ago

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