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maria [59]
3 years ago
11

Na-m; use m=2; and n=8

Mathematics
1 answer:
madreJ [45]3 years ago
3 0

Answer:  na - m = 8a - 2

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She played 8 games. Since she earned a total of 120 points and 15 points per game you would divide 120/15=8
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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
On a map, the distance between two historical markers is 4.5 inches, and 2.5 inches represents 10 miles.
Morgarella [4.7K]

Answer:

The actual distance between the historical markers is 18 miles.

Step-by-step explanation:

Given : On a map, the distance between two historical markers is 4.5 inches, and 2.5 inches represents 10 miles.  

To find : What is the actual distance between the historical markers?

Solution :

We have given that,

2.5 inches represents 10 miles.

i.e, 1 inch represent \frac{10}{2.5} miles.

1 inch = 4 miles.

Now, The distance between two historical markers is 4.5 inches.

The actual distance between the historical markers in 4.5 inch is

4.5 \text{ inch}=4.5\times 4\text{ miles}

4.5 \text{ inch}=18\text{ miles}

Therefore, The actual distance between the historical markers is 18 miles.

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3 years ago
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