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2 years ago

A solid gold ingot has a volume of 200 cm3 and a mass of 3.9 kg.

Mathematics

1 answer:

Contact [7]2 years ago

7 0

Step-by-step explanation:

convert 3.9 kg to grams

3.9×1000=3900 g

density = mass/ volume

= 3900/ 200

=19.5 g/cm3

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Which values are within the range of the piecewise-defined function?

musickatia [10]

Answer: y < 1

Step-by-step explanation:

$\begin{array}{c|c||l}\underline{x; x-3}&\underline{y=-x-2}&\\-3&-(-3)-2=1&\text{approaching but not including 1}\\-2&-(-2)-2=0&\\-1&-(-1)-2=-1&\end{array}$

The first function has the range of y < -4

The second function has the range of y = -3

The third function has the range of y < 1

The largest y-value is 1 and the smallest y-value is -∞, therefore the range (y-values) are from -∞ to 1 → y < 1

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3 years ago

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X + 3/ 5 = 2 -5 -3 7 13

ahrayia [7]

X 3/5 =2x+15=2x=15-2x=13

answer 13

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3 years ago

Which series of transformations will not map figure H onto itself?

chubhunter [2.5K]

Answer:

(x + 0, y − 2), reflection over y = 1

Step-by-step explanation:

H will be shifted down 2 units and then reflected over y = 1, which maps H into itself

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3 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

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3 years ago

The standard form of the equation of a parabola is y= x2 - 8x + 29.

fomenos

Answer:

Step-by-step explanation:

Put brackets around the first two tems.

y = (x^2 - 8x) + 29

Take 1/2 coefficient of the linear term -8. Square that result. Add it inside the brackets.

1/2 (- 8) = - 4

(- 4)^2 = 16

y = (x^2 - 8x + 16) + 29

Subtract 16 outside the brackets.

y = (x^2 - 8x + 16) + 29 - 16

Do the subtraction

y = (x^2 - 8x + 16) + 13

Represent what is inside the brackets as a square.

y = ( x - 4)^2 + 13

The answer is A

7 0

3 years ago