Answer:
Minimum value of function 
is 63 occurs at point (3,6).
Step-by-step explanation:
To minimize :
Subject to constraints:
Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line
Eq (2) is in green in figure attached and region satisfying (2) is below the green line
Considering 
, corresponding coordinates point to draw line are (0,9) and (9,0).
Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line
Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)
Now calculate the value of function to be minimized at each of these points.
at A(0,9)
at B(3,9)
at C(3,6)
Minimum value of function is 63 occurs at point C (3,6).
4x = 14y
y = 4/14(x)
y = 2/7(x) slope = 2/7
<span>-2x+7y=14
7y = 2x + 14
y = 2/7(x) + 2 slope = 2/7
parallel lines, slope is the same
both lines have slopes equal 2/7
answer
</span><span>parallel</span>
Answer:
Answer : A
Step-by-step explanation:
The given data is 25 th percentile is 64, 50th percentile is 74 and 75 th percentile is 80.
percentage : 25 50 75
score : 64 74 80
Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.
If the number of observations is odd, then the median is observation
term
If the number of observations is even, then the median is observation and observations.
given n=3, middle term is '74'
In this given data the median is (M) = 74
Interquartile range IQR = median of upper half-median of lower half
= 80-64
= 16
IQR = 16
Option B model shows the percent of beads that are blue.
Solution:
Fraction of beads blue = 
To convert it into percent multiply the fraction by 100.
Cancel the common factors, we get
= 20%
This means total number of boxes 100 and shaded in blue color 20.
Therefore option 2 represents 
.
Hence option B model shows the percent of beads that are blue.
Answer:
Thanks you
Step-by-step explanation:
