Answer:
i dont know what set a or b is...I would love to help you though...see below.
Step-by-step explanation:
Mean is best used for a data set with numbers that are close together.
The median is the midpoint value of a data set, where the values are arranged in ascending or descending order.
In addition, the standard deviation, like the mean, is normally only appropriate when the continuous data is not significantly skewed or has outliers.
You should use the mode if the data is qualitative (colour etc.) or if quantitative (numbers) with a clearly defined mode (or bi-modal). It is not much use if the distribution is fairly even.
This can be useful if you are measuring a variable that has either a critical low or high threshold (or both) that should not be crossed. The range will instantly inform you whether at least one value broke these critical thresholds. In addition, the range can be used to detect any errors when entering data.
Quantile classification is ideal for ordinal data. When you have a clear ordering of the variables, then this is one of the advantages of quantity classification. If you want to rank data into categories such as high, medium, and low, this is another opportunity to use quantile classification
Answer:
(-2, 5), x = -2, y = 5
Step-by-step explanation:
When x = -2 and y = 5 on both equations, the equations become true.
Answer:
a) P(z<-0.66) = 0.2546
b) P(-1<z<1) = 0.6826
c) P(z>1.33) = 0.9082
Step-by-step explanation:
Mean = 300
Standard Deviation = 75
a) Less than 250 hours
P(X<250)=?
z = x - mean/ standard deviation
z = 250 - 300 / 75
z = -50/75
z = -0.66
P(X<250) = P(z<-0.66)
Looking for value of z = -0.66 from z score table
P(z<-0.66) = 0.2546
b. Between 225 and 375 hours
P(225<X<375)=?
z = x - mean/ standard deviation
z = 225-300/75
z = -75/75
z = -1
z = x - mean/ standard deviation
z = 375-300/75
z = 75/75
z = 1
P(225<X<375) = P(-1<z<1)
Looking for values from z score table
P(-1<z<1) = P(z<1) - P(z<-1)
P(-1<z<1) = 0.8413 - 0.1587
P(-1<z<1) = 0.6826
c. More than 400 hours
P(X>400) =?
z = x - mean/ standard deviation
z = 400-300/75
z = 100/75
z = 1.33
P(X>400) = P(z>1.33)
Looking for value of z = 1.33 from z-score table
P(z>1.33) = 0.9082
Answer:
2
Step-by-step explanation:
Answer:
5, 6, 7, 8, 9, 10, 11 and 12 are the natural numbers between 5 and 12 including them, therefore Jane wrote 8 numbers. natural numbers start at positive 1 and go up by whole numbers infinitely, hope this helps
