Answer:JT=15
Step-by-step explanation:
Answer:
yes it's a solution. I think. I don't really know this
The simplified form for (3x² + 2y² - 5x + y) + (2x² - 2xy - 2y² -5x + 3y) is (5x² + 0y² - 10x + 4y - 2xy).
<h3>A quadratic equation is what?</h3>
At least one squared term must be present because a quadratic is a second-degree polynomial equation. It is also known as quadratic equations. The answers to the issue are the values of the x that satisfy the quadratic equation. These solutions are called the roots or zeros of the quadratic equations. The solutions to the given equation are any polynomial's roots. A polynomial equation with a maximum degree of two is known as a quadratic equation, or simply quadratics.
<h3>How is an equation made simpler?</h3>
The equation can be made simpler by adding up all of the coefficients for the specified correspondent term through constructive addition or subtraction of terms, as suggested in the question.
Given, the equation is (3x² + 2y² - 5x + y) + (2x² - 2xy - 2y² -5x + 3y)
Removing brackets and the adding we get,
3x² + 2x² + 2y² - 2y² + (- 5x) + (- 5x) + y + 3y + (- 2xy) = (5x² + 0y² - 10x + 4y - 2xy)
To learn more about quadratic equations, tap on the link below:
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Answer:
No
Step-by-step explanation:
The equation of a circle with center (a,b) and radius r is given as:
If a given point (x,y) does not lie on this circle, it will not satisfy its equation.
This means the distance from the point to the center is not equal to the radius.
It is either less or greater than the radius.
Hence you cannot write the equation of the circle.
The question is for any rational function. I give one example in picture below. There we can see that first part of the "rule" is true. we indeed have vertical asymptotes at every x value where denominator is zero in this case x = 3 and x = 1. but second part of the rule is not true. we can see that if we inverse x ( we have factor that looks like a - x we get positive function between asymptotes.
Answer is False
