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jasenka [17]
2 years ago
7

Please answer Quickly

Mathematics
1 answer:
Mashcka [7]2 years ago
8 0
The answer is 21

By comparing the 4 vertices you can determine the rectangle x-length and y-length. The coordinate for the vertice is:
1,+4i
-2, +4i
-2, -3i
1, -3i

From the coordinate, you can see there are 2 x coordinate(1 and -2) and 2 y coordinate(4i and -3i) that used.
The x-length would be: 1 - (-2)= 3
The y-length would be: 4i- (-3i)= 7i

Then the area of the rectangle would be:
area= x-length * y-length= 3*7=21
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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

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AlekseyPX

Answer:

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Step-by-step explanation:

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