Here are the monthly charges for Jo's mobile phone

1 answer:

8 0

Jo's Mobile Plan:
Fixed monthly charge = £16
Monthly 150 free minutes, post that 13p (or £0.13) per minute,
Monthly 150 free texts, post that 15p (or £0.15) per text
Jo's mobile phone usage details:
170 minutes of calls
182 texts
Total Charges for Jo = Fixed Monthly Charge + Charges for Calls + Charges for Texts
⇒ Total Charges for Jo = 16 + (170-150) × 0.13 + (182-150) × 0.15
⇒ Total Charges for Jo = 16 + (20) × 0.13 + (32) × 0.15
⇒ Total Charges for Jo = 16 + 2.6 + 4.8
⇒ Total Charges for Jo = 23.4
Hence, Jo should be charged £23.4 for the month.

Hope this helps !

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LT1 10th grade level

Anton [14]

Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

$\overline{AE}$ / $\overline{AB}$ = $\overline{FA}$ / $\overline{AC}$ = $\overline{EF}$ / $\overline{BC}$

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides $\overline{AE}$ / $\overline{AB}$ = $\overline{FA}$ / $\overline{AC}$

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

$\overline{AE}$ / $\overline{AB}$ = $\overline{FA}$ / $\overline{AC}$ = 50 ft. /(100 ft.) = $\overline{EF}$ / $\overline{BC}$ = $\overline{EF}$ /120 ft.

$\overline{EF}$ = 120 ft. × 50 ft./(100 ft.) = 60 ft.

$\overline{EF}$ = 60 ft.

The distance between the pirate and the treasure, $\overline{EF}$ = 60 ft.

4 0

2 years ago

Enter the product.<br> 27<br> X 7

Kay [80]

Answer:

189

Step-by-step explanation:

7 x 27 = 189

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