Answer:
The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08
Step-by-step explanation:
To solve this exercise we have to know that the probability is calculated by dividing the number of favorable events by the number of possible events.
f = favorable events
we will count how many numbers between 1 and 50 have the same number in the ones place in the tens place
11 ; 22 ; 33 ; 44
as we can see there are 4 numbers
f = 4
p = possible events
the number of possible events is given by the number of cards in the deck
p = 50
4/50 = 0.08
The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08
Answer:
plz can you take a pic and upload it for me to work it out
thanks
Step-by-step explanation:
5x+6y=18
5x=18-6y
x=(18-6y)/5
Use that in the other equation
18(18-6y)/5 - 15y = 36
64.8-21.6y - 15y = 36
28.8=36.6y
.7868=y
Now put that number in for y on the first equation
5x+6(.78) = 18
5x + 4.68 = 18
5x = 13.32
x = 2.66
and y = .78
Answer:
x = 1 and y = 6
Step-by-step explanation:
3x - 2y = -9 ........................... eqn 1
4x + 3y = 22 ........................... eqn 2
to eleminate y, multiply eqn 1 by 3 and eqn 2 by 2
(3x - 2y = -9) × 3
(4x + 3y = 22) × 2
9x - 6y = -27 ........................... eqn 3
8x + 6y = 44 ........................... eqn 4
Add eqn 3 and 4 together and we get
17x = 17
x = 17/17
x = 1
To get y, substitute 1 for x in any of the eqns
taking eqn 4
8(1) + 6y = 44
8 + 6y = 44
6y = 44 - 8
6y = 36
y = 36/6
y = 6
