Since this is not a rational function (with undetermined values in the denominator), but just a normal expression, we can just substitute t with the value toward which the function is approaching. Since this is a continuous function, it doesn't matter from which side it's approaching 0. In this case, let t=0, then sin(4t)=0, cos(4t)=1, then -2 sin^2(4t)+2tcos(4t)=0.
$4440 i think, im not sure
Slope
-9+7 -2
—— = ——
-5+10 5
Equation of a line
y+7=-2/5(x+10)
y+7=-2/5x-4
y=-2/5x-11
You can get all the terms on one side, and then solve for x by any means:

Factor out a -2:

Factor this equation:

I will use the AC method. To use it, first multiply a and c (in ax^2 + bx +c):

Now, look for two numbers that multiply to -12 and add to -11. Obviously these numbers are -12 and 1. (-12*1 = -12 and -12+1 = -11). Now, because of rules, you set it up in a Punnett square:
4x^2 -12x
x -3
Now, we find common factors of the terms in rows:
_x_______-3__
4x| 4x^2 -12x
1 | x -3
So, you can use this to write an equivalent expression to the quadratic given:

Now, we known the factors are (solve for x):
3 and -1/4.
Answer:
answer C i got it right 100%
Step-by-step explanation: