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dlinn [17]
3 years ago
9

Need help with this thank you

Mathematics
1 answer:
Mkey [24]3 years ago
5 0
A.b=15
B.m=18/11
C.b=28/3
D.k=18/7
E.j=3/2
F.m=7/2
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If using the method of completing the square to solve the quadratic equation
Assoli18 [71]

Answer:

The number would have to be added is 2

Step-by-step explanation:

To find the form of the completing square of the quadratic function:

  • Divide the coefficient of x by 2
  • Square the quotient
  • Subtract the numerical term from the square of the quotient

Let us do these steps with our question

∵ x² - 2x - 1 = 0

→ Divide the coefficient of x by 2

∵ The coefficient of x is -2

∴ -2 ÷ 2 = -1

→ Square the -1

∵ (-1)² = 1

→ Subtract the numerical term from 1

∵ The numerical term = -1

∵ 1 - (-1) = 1 + 1 = 2

∴ We must add 2 to -1 to get 1

→ (x² - 2x - 1 + 2) - 2 = 0

→ (x² - 2x + 1) = 2

→ (x - 1)² = 2

The number would have to be added is 2

4 0
3 years ago
Ellus
Julli [10]

Answer:

range = 10

Step-by-step explanation:

The range is the difference between the largest and smallest values in the data set.

largest value = 12

smallest value = 2

range = 12 - 2 = 10

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
The area of the smaller triangle is about 270 ft2. Which is the best approximation for the area of the larger triangle?
vampirchik [111]
The assumption here is that, both triangles are similar.  Now, if that's the case,

\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{ccccllll}&#10;&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array}\\\\&#10;-----------------------------

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{small}{large}\qquad \cfrac{25}{35}\implies \stackrel{simplified}{\cfrac{5}{7}}\qquad \qquad \cfrac{5}{7}=\cfrac{\sqrt{270}}{\sqrt{x}}\implies \cfrac{5}{7}=\sqrt{\cfrac{270}{x}}&#10;\\\\\\&#10;\left( \cfrac{5}{7} \right)^2=\cfrac{270}{x}\implies \cfrac{5^2}{7^2}=\cfrac{270}{x}\implies x=\cfrac{7^2\cdot 270}{5^2}
7 0
4 years ago
Read 2 more answers
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