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natta225 [31]
3 years ago
10

Jess has 32 dollars to spend at the festival she spends 6 dollars on food and the rest on games. If each game costs 2 dollars ho

w many games does she play?
Mathematics
1 answer:
Oksanka [162]3 years ago
7 0
She plays 8 games with a total of $1 as a remainder!
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Y=3x+4 y=-2x-1 mathaaaaa
valentinak56 [21]

Answer:

the answer is x=−1 and y=1

Step-by-step explanation:

hoped I helped:)

7 0
3 years ago
The solution to the inequality 5x - 4 > 21 is represented by which number line?
andrew-mc [135]

Answer:

Step-by-step explanation:

Start with the given inequality and solve it for x.

First, add 4 to both sides:  5x > 25

Next, divide both sides by 5:  x > 5

The solution (set) is x > 5.

7 0
3 years ago
Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen
vladimir1956 [14]

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

6 0
4 years ago
A poll asked 1057 American adults if they believe there was a conspiracy in the assassination of President Kennedy, and found th
AVprozaik [17]

Answer:

The 95% confidence interval of the proportion of Americans who believe in the conspiracy is  0.551<  p <  0.610

Step-by-step explanation:

From the question we are told that

   The sample size is  n =1057

   The number that believe there was a conspiracy is  k = 614

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{614}{1057 }

=>   \^ p = 0.5809

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E = 1.96 * \sqrt{\frac{0.5809 (1- 0.5809)}{1057} }    

=>   E = 0.02975  

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.5809 - 0.02975<  p <  0.5809 + 0.02975

=>    0.551<  p <  0.610

4 0
3 years ago
I need help on 5 and 6 geometry
DiKsa [7]
That's 5 and that's 6

4 0
3 years ago
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