First, do 100-14 to find out how much percent doesn't get the coupon= 85
then find 85% of 64= 54.4
finally, your answer is: 54.4
Let's solve this problem step-by-step.
First of all, let's establish that supplementary angles are two angles which add up to 180°.
Therefore:
Equation No. 1 -
x + y = 180°
After reading the problem, we can convert it into an equation as displayed as the following:
Equation No. 2 -
3x - 8 + x = 180°
Now let's make (y) the subject in the first equation as it is only possible for (x) to be the subject in the second equation. The working out is displayed below:
Equation No. 1 -
x + y = 180°
y = 180 - x
Then, let's make (x) the subject in the second equation & solve as displayed below:
Equation No. 2 -
3x - 8 + x = 180°
4x = 180 + 8
x = 188 / 4
x = 47°
After that, substitute the value of (x) from the second equation into the first equation to obtain the value of the other angle as displayed below:
y = 180 - x
y = 180 - ( 47 )
y = 133°
We are now able to establish that the value of the two angles are as follows:
x = 47°
y = 133°
In order to determine the measure of the bigger angle, we will need to identify which of the angles is larger.
133 is greater than 47 as displayed below:
133 > 47
Therefore, the measure of the larger angle is 133°.
Answer: F (False)
Step-by-step explanation:
Jointly variation has the following form:
y=kxz
Where k is a constant of propotionality.
Substitute values:
If y=16, x=4 and z=2, then k is:
If x=-8 and z=-3 the the value of y is:
Then the answer is FALSE.
Answer:
Step-by-step explanation:
Let the function of quantity in the lung of air be A(t)
So 
so, A(t) = Amax sin t + b
A(t) = 2.8t⇒ max
A(t) = 0.6t ⇒ min
max value of A(t) occur when sin(t) = 1
and min value of A(t) = 0
So b = 0.6
and A(max) = 2.2
at t = 2 sec volume of a is 0.6
So function reduce to
and t = 5 max value of volume is represent
so,
when t = 5
so the equation becomes
Answer:
because of a geometry theorem since the angles have the same arc length they have the same angle measure
<u>20 degrees</u>
