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Sergio039 [100]
2 years ago
13

What would be the first step to solve for n in the equation 3n-7=30?

Mathematics
2 answers:
taurus [48]2 years ago
4 0
The first step would be to add 7 to both sides.
3n-7=30
add 7
3n=37
divide by 3
n=12.33
olya-2409 [2.1K]2 years ago
3 0

Answer:

n = 37/3

Step-by-step explanation:

3n = 30 +7

3n = 37

n = 37/3

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What is another way to write the number 47 (tens and ones)
Nadusha1986 [10]
47 (numeral)
forty seven (in words)
40 + 7 (expanded form)
4 tens and 7 ones (tens and ones)

*Hope that helps XD *
8 0
3 years ago
Read 2 more answers
If the present value of a growing perpetuity is 214, the required rate of return is 10%, and growth rate is 3%, what is the cash
Kryger [21]

The cash flow in year 1 is $15.

<h3>What is the cash flow in year 1?
</h3>

A growing perpetuity increases continuously and indefinitely.

Cash flow = present value x (rate of return - growth rate)

214 x (10% - 3%)

214 x 0.07 = $15

To learn more about present value, please check: brainly.com/question/17322936

#SPJ1

3 0
2 years ago
what is the equation of the line, in point-slope form, that passes through the given point and has the given slope ? point (7,3)
Maru [420]

Answer:

y-3 = 4/7(x-7)

Step-by-step explanation:

Point slope form is

y-y1 = m(x-x1)

We know the slope (4/7)

and a point (7,3)

Lets substitute into the equation

y-3 = 4/7(x-7)

6 0
3 years ago
Can you answer this question as soon as possible.
Whitepunk [10]

Answer:

The intensity of the first earthquake is 6.31 times the second one

Step-by-step explanation:

The given formulae is M=log(\frac{I}{S})

Here for both the earthquakes the value of S is same.

Let the Intensity of the first earthquake be I1 and the second be I2.

Given M1=7.5

M2=6.7

Now  M1=log(\frac{I1}{S})------1

M2=log(\frac{I2}{S})-----2

Now subtract 1 and 2 we get

M1-M2=log(\frac{I1}{I2})

I1/I2=10^{M1-M2}

I1=I2(10^{0.8}

I1=I2*6.31

6 0
3 years ago
16. What is the area of the shaded region in terms of Tr? [20 points]
tangare [24]
Area of the circle outside
= πr2
= π(5)2
=25 π

Area of the bigger circle inside
= π x(3)2
= 9 π
Area of the smaller circle inside
= π x (2)2
= 4 π

Area of shaded region
= 25π - 9π - 4π
= 12π square unit
6 0
2 years ago
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