All categories

3 years ago

Answer ? For this question

Mathematics

1 answer:

Mademuasel [1]3 years ago

6 0

Orange box:

The incorrect statement is B. The theoretical probability is the probability of an event occurring that is expected. In this case, the theoretical probability of selecting a dime is 4/25.

Purple box:

The incorrect statement is C. The difference between the theoretical and experimental probability is not 1/10. The difference between the experimental and theoretical probability is 0.015 or 3/200.

6/25 = 0.24

9/40 = 0.225

0.24 - 0.225 = 0.015

Hope this helps!! :)

You might be interested in

Fill in the boxes below with the numbers 1-5.

Alja [10]

Answer:

4 - 2 - 3 - 1 - 5

Step-by-step explanation:

The substitute method consists of the following steps:

Solve for either x or y in one of the equations.
Substitute the expression you got into the other equation
Simplify and solve for the variable that remains.
Back substitute and solve for the first variable.
Check your solution

3 0

3 years ago

Read 2 more answers

A amusement park charges $35.50 for admission. On Saturday, 3,247 people visited the park. On Sunday, 3,542 people visited the p

garik1379 [7]

Answer:

$241009.50

Step-by-step explanation:

35.50*3247=115268.50

35.50*3542=125741.00

+________

241009.5

6 0

3 years ago

Dentify as an increase or decrease. Then find the percent of increase or decrease. If necessary, round to the nearest percent.

love history [14]

Answer:

Step-by-step explanation:

The difference is 130-150 = -20, a decrease.

-20/150 ≅ -0.133, a decrease of 13.3%

4 0

3 years ago

Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

3 years ago

Please help me idk this

GarryVolchara [31]

Answer:

Step-by-step explanation:

$A=\dfrac{bh}{2}\\\\A=117\ cm^2\\b=13\ cm$

Substitute:

$117=\dfrac{13h}{2}$ <em>multiply both sides by 2</em>

$234=13h$ <em>divide both sides by 13</em>

$18=h\to h=18\ cm$

6 0

3 years ago