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maw [93]
3 years ago
8

If f(x) =- 2x + 5, find f(4x)​

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0

Answer:

f(4x)=-8x+5

Step-by-step explanation:

We are given the function:

f(x)=-2x+5

And we want to find:

f(4x)

So, by substitution, we acquire:

f(4x)=-2(4x)+5

Multiply. So, our answer is:

f(4x)=-8x+5

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Read 2 more answers
Inverse laplace of L^-1 {5s/s^2 + 3s - 4}​
Salsk061 [2.6K]

Answer:

e^t+e^{-4t}

Step-by-step explanation:

We have to simplify the original function using partial fraction, hence:

\frac{5s}{s^2+3s-4} =\frac{5s}{(s-1)(s+4)}\\\\=\frac{A}{s-1}+\frac{B}{s+4}\\\\Therefore:\\\\\frac{A(s+4)+B(s-1)}{(s-1)(s+4)}=\frac{5s}{(s-1)(s+4)}\\\\Eliminating\ the \ denominator:\\\\A(s+4)+B(s-1)=5s\\\\substitute\ s=1:\\\\A(1+4)+B(1-1)=5(1)\\\\5A=5\\\\A=1\\\\tsubstitute\ s=-4:\\\\A(-4+4)+B(-4-1)=5(-4)\\\\-5B=-20\\\\B=4\\\\Therefore\ substituting\ A\ and\ B\ gives:\\\\\frac{5s}{s^2+3s-4}=\frac{1}{s-1}+ \frac{4}{s+4}\\\\

From\ Laplace\ inverse:\\\\But\ L^{-1}[\frac{1}{s-a} ]=e^{at}\\\\Hence:\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=L^{-1}[\frac{1}{s-1} ]+L^{-1}[\frac{4}{s+4} ]=e^{t}+4e^{-4t}\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=e^{t}+4e^{-4t}

5 0
3 years ago
Need help with this Question ​
Mrrafil [7]
Answer C

| (5)(2)+(0)(2) = 10, (5)(-1)+(0)(-2) = -5 |
| |
| (3)(2)+(-5)(2) = -4, (3)(-1)+(-5)(-2) = 7 |
5 0
3 years ago
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