It should be 2 ..............
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer:
x=1
Step-by-step explanation:
Answer:
y = 4/3
Step-by-step explanation:
The two equations can be added to eliminate x:
(0.1x +0.5y) + (-0.1x -0.2y) + (1.2) +(-0.8)
0.3y = 0.4 . . . . . simplify
Divide by the coefficient of y to find y:
y = 0.4/0.3
y = 4/3
Answer:
B. 31.4
Step-by-step explanation:
● you use the equation to find the circumstance of a circle so 2(pi)r.
● plug in the numbers into the equation 2(3.14)(5)
● evaluate. 2(15.70) = 31.4
