Here we have to find the probability
. Now express the probability in terms of standard normal cumulative distribution function. That is
.

Now you can look up the probability from the standard normal tables. Its value is

Answer:
none above
Step-by-step explanation:
Step-by-step explanation:

Answer:
picture?
Step-by-step explanation:
Answer:
x ≈ ±20.086/√(t - 1)
Step-by-step explanation:
ln(t - 1) + ln(x²) = 6
Recall that lnu + lnv = ln(uv). Then
ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6
Take the natural antilogarithm of each side
(t - 1)x² = e⁶
Divide each side by t - 1
x² = e⁶/(t-1)
Take the square root of each side
x = ±e³/√(t - 1)
x ≈ ±20.086/√(t - 1)