Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
Answer:
False.
Explanation:
When we declare a variable as reference type we have to initialize that variable otherwise the compiler will give error that the reference variable is not initialized.You also cannot initialize the variable Foo& with NULL value because it is a reference variable and we have to initialize it.
On the other there is no need to initialize the variable Foo * since it is a pointer it can also store NULL value.
So the answer is only Foo* can store NULL value not Foo &.
Big hero six was the greatest kid movie ever invented like there is no question about that I love that movie
Answer: I am pretty sure it's RAM
Explanation:
I'm not 100% positive bc I haven't gotten my scores back yet but I think that's it.
