Answer:
Step-by-step explanation:
From the given information:
Let assume that:
A be the distribution of contractor A and B be the distribution for contractor B
Then:


A
triangular distribution.
(a) Suppose that Jonah submits a bit of $750000;
The probability that Jonah win = P( B < 750000) * P(A < 750000)


Then,
P(B < 750000) = P(Z < 1)
P(B < 750000) = 0.841
To simplify P(A < 750000); we take 800000 as 8, and 725000 as 7.25




![= \dfrac{1}{1.25} \Big [ \dfrac{a^2}{2}- 6a \Big ] ^{7.25}_{6} + \dfrac{1}{0.75} \Big [ 8a - \dfrac{a^2}{2} \Big ] ^{7.5}_{7.25}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B1%7D%7B1.25%7D%20%5CBig%20%5B%20%5Cdfrac%7Ba%5E2%7D%7B2%7D-%206a%20%5CBig%20%5D%20%5E%7B7.25%7D_%7B6%7D%20%2B%20%20%5Cdfrac%7B1%7D%7B0.75%7D%20%5CBig%20%5B%208a%20-%20%5Cdfrac%7Ba%5E2%7D%7B2%7D%20%5CBig%20%5D%20%5E%7B7.5%7D_%7B7.25%7D)
= 0.625 + 0.2083
= 0.833
∴
The probability that Jonah wins = P( B < 750000) * P(A < 750000)
= 0.841 × 0.833
= 0.70055
= 70.06%
The probability that Jonah will win a bid = 70.06%
P(A win the bid) = P (A > 750000 ) * P(B < 750000)
P(A win the bid) = 0.841 * (1- 0.833)
P(A win the bid) = 0.14044
P(A win the bid) = 14.04%
P(B win the bid) = P(A < 750000) * P( B > 750000)
P(B win the bid) = 0.833 * ( 1 - 0.841)
P(B win the bid) = 0.13245
P(B win the bid) = 13.25%
∴
"A" win the bid is 14.04% and "B" win the bid is 13.25% respectively.