500 (the current collection) + 10 (the weekly addition) x 20 (weeks to add)
500 + 10*20 (Multiplication comes before addition)
500+200
700
The final step in solving the inequality is to divide through by -2 and flip the sign
<h3>Solving Inequalities </h3>
From the question, we are to determine the final step in solving the inequality
The given inequality and the steps for solving are
Step 1: –10 + 8x < 6x – 4
Step 2: –10 < –2x – 4
Step 3: –6 < –2x
The final step will be to divide both sides of the inequalities by -2 and then flip the sign
That is,
–6 < –2x
Divide both sides by -2 and flip the sign
3 > x
OR
x < 3
Hence, the final step in solving the inequality is to divide through by -2 and flip the sign
Learn more on Solving inequalities here: brainly.com/question/246993
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Answer:
If the shape of end face has n sides
Then, in total, there are n+2 faces
Using that formula
Faces in 20-sided polygon = n+2 = 20+2 = 22
Step-by-step explanation:
Pls vote as brainliest
Answer:
I have made it in above pic hope it helps
Step-by-step explanation:
there is no need to rationalize simply add √3-√5=1-√2
<u>Given</u><u> info</u><u>:</u><u>-</u>
Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.
Find the perimeter of the field ?
<u>Explanation</u><u>:</u><u>-</u>
Given that
rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.
Let consider a rhombus ABCD
Let AC = (d1) = 42 cm
Let BD = (d2) = 56 cm
We know that
The digonals of a rhombus bisects each other at 90°.
AC = AO+OC
⇛ AC = 2 AO = 2 OC
⇛ AO = OC = AC/2
⇛ AO = OC = 42/2 = 21 cm
and
BD = BO+OD
⇛ BD = 2 BO = 2 OD
⇛ BO = OD = BD/2
⇛ BO = OD = 56/2 = 28 cm
We have,
∆AOB is a right angled triangle
By Pythagoras theorem,
AB² = AO²+OB²
⇛ AB² = 21²+28²
⇛ AB² = 441+784
⇛ AB² = 1225
⇛ AB = ±√1225
⇛ AB = ±35
AB is the length of the side which cannot be negative.
AB = 35 cm
We know that
All sides are equal in a rhombus
⇛ AB = BC = CD = DA
As we know
The Perimeter of a rhombus = 4×Side units
The perimeter of the rhombus ABCD
⇛ 4AB = 4BC = 4CD = 4DA
⇛ 4×35 cm
⇛ Perimeter = 140 cm
<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>
