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3 years ago

Solve b+12≤26. Graph the solution

Mathematics

1 answer:

Vladimir79 [104]2 years ago

6 0

Answer:

The answer is

b≤14

So you make a filled in circle at 14, make the point for left from there.

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In a random sample of 250 students, 150 were in favor of longer hours at the school library. At 98% level of confidence, what is

Wewaii [24]

0.072 is the margin of error.

<h3>What is standard error?</h3>

The standard error (SE) of a statistic is the standard deviation of its sampling distribution or an estimate of that standard deviation.

According to the question,

In a random sample of 250 students,

p= 0.98 (or 98%) were in favor of longer hours at the school library.

The standard error of p(the sample proportion) is (approximately)

The standard error of p = $\sqrt{\frac{p(1-p)}{n} }$

p = 0.98

1 - p = 1 - 0.98 = 0.02

Here,

n = 250

The standard error of p = $\sqrt{ \frac{0.98 (0.02) }{250}$

The standard error of p ≈ 0.072

Therefore,

The margin of error is 0.072.

Learn more about is standard error here:

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1 year ago

The second part of the problem is where i need help. The answers i have there have been given by other tutors

tino4ka555 [31]

SOLUTION

From the given value

Since

$\sin u=\frac{7}{25}$

Then using trigonometrical ratios it follows

$\cos u=\frac{24}{25}$

Using hal -ngle it folows

$\begin{gathered} sin(\frac{u}{2})=\sqrt{\frac{1-\frac{24}{25}}{2}} \\ s\imaginaryI n(\frac{u}{2})=\sqrt{\frac{1}{50}} \end{gathered}$

Also

$\begin{gathered} cos(\frac{u}{2})=\pm\sqrt{\frac{1+\frac{24}{25}}{2}} \\ cos(\frac{u}{2})=\sqrt{\frac{49}{50}} \\ cos(\frac{u}{2})=7\sqrt{\frac{1}{50}} \end{gathered}$

Finally?

$\begin{gathered} \tan(\frac{u}{2})=\pm\sqrt{\frac{1-\frac{24}{25}}{1+\frac{24}{25}}} \\ \tan(\frac{u}{2})=\sqrt{\frac{1}{49}} \\ \tan(\frac{u}{2})=\frac{1}{7} \end{gathered}$

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Answer:

<h3 />

Step-by-step explanation:

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