Andre can make 6 small paper cranes in 30 minutes.
Step-by-step explanation:
Given data-
Time taken by Andre to build small cranes- 3minutes
Time taken to build large crane- 10 minutes
Total time allotted to him= 30 min
His preferences- Building one large crane and several small cranes.
The Inequality equation is 3c + 10 ≤ 30
Since his preference is to build atleast one large crane which takes 10 minutes, he is left with 30-10 = 20 minutes to build other small cranes.
For one crane he needs, 3 minutes
Hence, he can build 6 cranes in 18 minutes. Following this, he is left with 20-18= 2 minutes. Since he needs at least 3 min to build a small crane, he cannot build a small crane in the remaining 2 min.
he builds 6 small cranes in 30 minutes
<u>Alternatively,</u>
3c + 10 ≤ 30
Subtracting 10 from both sides
3c ≤ 20
The maximum value of c for which this equation remains valid is 6.
Thus, he builds a total of 6 cranes (small) in 30 minutes.
