5x^2 -2x +1 = 0
D = 4 -20 = -16
so this mean that the quadratic has no real solutions
I believe your answer is c
Answer:
There is descending of 8260 feet in altitude for all 4 balloons.
<h3>
Answer:</h3>
- C. (9x -1)(x +4) = 9x² +35x -4
- B. 480
- A. P(t) = 4(1.019)^t
Step-by-step explanation:
1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.
2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...
... (d+43) + d = 1003
... 2d = 960 . . . . . . . subtract 43
... d = 480 . . . . . . . . divide by 2
The second voyage lasted 480 days.
3. 1.9% - 1.9/100 = 0.019. Adding this fraction to the original means the original is multiplied by 1 +0.019 = 1.019. Doing this multiplication each year for t years means the multiplier is (1.019)^t.
Since the starting value (in 1975) is 4 (billion), the population t years after that is ...
... P(t) = 4(1.019)^t
Answer: 110 child tickets and 50 adult tickets were sold.
Step-by-step explanation:
Let x be the number of child tickets and y be the number of adult tickets.
then, According to the given information, we have
![7x+9y=1220------------(1)\\\\x=10+2y----------(2)](https://tex.z-dn.net/?f=7x%2B9y%3D1220------------%281%29%5C%5C%5C%5Cx%3D10%2B2y----------%282%29)
Substitute the value of x from (2) in (1), we get
![7((10+2y))+9y=1220\\\\\Rightarrow\ 70+14y+9y=1220\\\\\Rightarrow\ 23y=1220-70\\\\\Rightarrow\ 23y=1150\\\\\Rightarrow\ y=\dfrac{1150}{23}=50](https://tex.z-dn.net/?f=7%28%2810%2B2y%29%29%2B9y%3D1220%5C%5C%5C%5C%5CRightarrow%5C%2070%2B14y%2B9y%3D1220%5C%5C%5C%5C%5CRightarrow%5C%2023y%3D1220-70%5C%5C%5C%5C%5CRightarrow%5C%2023y%3D1150%5C%5C%5C%5C%5CRightarrow%5C%20y%3D%5Cdfrac%7B1150%7D%7B23%7D%3D50)
Now, put the value of y in (2), we get
![x=10+2(50)=110](https://tex.z-dn.net/?f=x%3D10%2B2%2850%29%3D110)
Hence, 110 child tickets and 50 adult tickets were sold.