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lilavasa [31]
3 years ago
7

*place holder since picture has the work*

Mathematics
1 answer:
ira [324]3 years ago
3 0

Answer:

A square.

Step-by-step explanation:

I plotted the points on Desmos and then connected them.

When connected, the lines form a square.

[Picture Below]

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The Los Angeles Times regularly reports the air quality index for various areas of Southern California. A sample of air quality
egoroff_w [7]

Answer:

1. (a) 32     (b) 8

2. (a) 48.33    (b) 92.75    (c) 9.63

3.  We observe that sample mean of air quality index in Pomona is higher that that of Anaheim which indicates that the level of air pollution is higher in Pomona and there is more health concern here.

On the other hand, the variation in air quality index is higher in Anaheim than in Pomona as Anaheim has higher variance and standard deviation for air quality index which means that there are not much fluctuations in air quality index in Pomona.  

Step-by-step explanation:

First arranging our data of air quality index values for Pomona in ascending order, we get : 28, 42, 45, 48, 49, 50, 55, 58, 60.

  1. (a) Range is given by the formula :

                      Highest value in data - Lowest value in data = 60 - 28 = 32

        (b) Interquartile rage = Third quartile - First quartile

                                           = Q_3 - Q_1

             Q_1 =  (\frac{n-1}{4} )^{th} observation in the data = 2^{nd} obs. { Because n = 9}

                 Therefore, Q_1 = 42.

             Q_3 = (3Q_1)^{th} obs. = (3 x 2 ) = 6^{th} obs = 50

             So, Interquartile rage = 50 - 42 = 8.

     2. (a) Sample mean formula =  \frac{\sum X_i}{n} = \frac{28+ 42+ 45+ 48+ 49+ 50+ 55+ 58+ 60}{9} = 48.33

         (b) Sample variance formula = \frac{\sum (X_i - Xbar)^{2}}{n-1} where Xbar = Sample mean

                                                         = 92.75

          (c) Sample standard deviation  formula = \sqrt{variance} = \sqrt{92.75} = 9.63.

     3. Given that a sample of air quality index readings for Anaheim has   sample mean of 48.3, a sample variance of 136, and a sample standard deviation of 11.66.

We observe that sample mean of air quality index in Pomona is higher that that of Anaheim which indicates that the level of air pollution is higher in Pomona and there is more health concern here.

On the other hand, the variation in air quality index is higher in Anaheim than in Pomona as Anaheim has higher variance and standard deviation for air quality index which means that there are not much fluctuations in air quality index in Pomona.  

                                       

7 0
2 years ago
________________________________
KIM [24]

Answer:

The Red block is the answer

Step-by-step explanation:

6 0
2 years ago
Here is the next questions brainliest to the first who answer it
qaws [65]

Answer:

Look at the attachment

7 0
3 years ago
Simplify the expressions by combining like terms<br><br> 4r + 9r - 11r + 7r
konstantin123 [22]
9r
Explanation:
4r + 9r = 13r
13r-11r = 2r
2r + 7r = 9r
4 0
3 years ago
Read 2 more answers
What is the difference between 0.0032 and 0.32? and which one is greater?
mariarad [96]
.0032 = 0.32%
.32 = 32%
.32 is 100 times greater than .0032, therefore, 0.32 is greater
8 0
3 years ago
Read 2 more answers
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