Ask question

Ask question

All categories

4 years ago

15

What is 20000 divided 10?

2 answers:

Marina86 [1]4 years ago

8 0

20000:10=2000 because 10 has one 0 so you take off one 0 from 20000

spin [16.1K]4 years ago

5 0

20,000/10=2,000 :)
Good luck

You might be interested in

What is the median of 81,83,91, and , 94

kotegsom [21]

The answer is going to be 85.

7 0

3 years ago

Read 2 more answers

The sum of two numbers is 72. The greater number is 8 more than the smaller number. Which equation can be used to solve for the

yKpoI14uk [10]

Lets smaller number is x
<span>The greater number is 8 more than the smaller number : x + 8
</span><span>The sum of two numbers is 72: x +( x + 8)= 72

answer
</span><span>x + (x + 8) = 72</span>

6 0

3 years ago

Read 2 more answers

Radian question please answer asap!!!

anygoal [31]

Answer: how about 90

Step-by-step explanation:

Its a 360 if you multiply 90×4 you get 360 every side is 90 degrees

5 0

3 years ago

There are some children playing at the park when 4 more arrive and begin playing. Now there are 28 children playing at the park.

lisov135 [29]

Currently there are 28 children playing. Until a moment ago, 4 of those 28 werent there. To find out how many there were a moment ago, we have to exclude those 4 kids that just came — or subtract the number of kids that just came from the number of kids currently playing.

28-4=24

We can check: 24+4=28

5 0

3 years ago

The angle 0 lies in Quadrant II . <br>Cos 0 = <br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexF

mel-nik [20]

Answer:

$\tan(\theta)=\frac{-\sqrt{5}}{2}$

Step-by-step explanation:

Since we are in quadrant 2, sine is positive. Since sine is positive and cosine is negative, then tangent is negative.

Now I'm going to find the sine value of this angle given using one of the Pythagorean Identities, namely $\sin^2(\theta)+\cos^2(\theta)=1$ .

If given $\cos(\theta)=\frac{-2}{3}$ , then we have $\sin^2(\theta)+(\frac{-2}{3})^2=1$ by substitution of $\cos(\theta)=\frac{-2}{3}$ .

Let's solve:

$\sin^2(\theta)+(\frac{-2}{3})^2=1$ for $\sin(\theta)$ .

$\sin^2(\theta)+\frac{4}{9}=1$

Subtract 4/9 on both sides:

$\sin^2(\theta)=1-\frac{4}{9}$

Simplify:

$\sin^2(\theta)=\frac{5}{9}$

Square root both sides:

$\sin(\theta)=\sqrt{\frac{5}{9}}$

$\sin(\theta)=\frac{\sqrt{5}}{\sqrt{9}}$

$\sin(\theta)=\frac{\sqrt{5}}{3}$

===========

$\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=\frac{\frac{\sqrt{5}}{3}}{\frac{-2}{3}}$

Multiplying top and bottom by 3 gives:

$\tan(\theta)=\frac{\sqrt{5}}{-2}$

I'm going to move the factor of -1 to the top:

$\tan(\theta)=\frac{-\sqrt{5}}{2}$

7 0

3 years ago