Shara collected two different data sets and label them dataset S and data said T.

Deon throws a ball into the air. The height h of the ball, in meters, at time t seconds is modeled by the function h(t)= -5t^

Ket [755]

Answer: no

Step-by-step explanation:

7 0

2 years ago

The volume of this right prism is 2,500 ft³. What is the height, x, of the prism? x = ft

Natalka [10]

The height x of the right prism is 10 ft if the volume of this right prism is 2,500 ft³.

<h3>What is a rectangular prism?</h3>

It is defined as the six-faced shape, a type of hexahedron in geometry.

It is a three-dimensional shape. It is also called a cuboid.

From the figure:

Volume = 2500 cubic ft

(10)(x)(25) = 2500

250x = 2500

x = 10 ft

Thus, the height x of the right prism is 10 ft if the volume of this right prism is 2,500 ft³.

Learn more about the rectangular prism here:

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6 0

2 years ago

How much cardboard is needed to make the tissue box above? Square inches 8 3 3

Katen [24]

The amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

<h3>What is the surface area of cuboid?</h3>

Let the three dimensions(height, length, width) be x, y,z units respectively.

The surface area of the cuboid is given by

$S = 2(a\times b + b\times c + c\times a)$

For this case, tissue box is almost cuboid shaped.

Also, its dimensions are given being 8 inches, 3 inches and 3 inches.

Suppose we measure the amount of cardboard needed in terms of area, then, the amount of cardboard needed to make that box(without any whole, full cuboid) is equal to the area of its surface(either outer or inner if we assume 0 inches thickness of cardboard),

Thus, we get:

Amount of cardboard needed = surface area of cuboid box with dimensions 8 by 3 by 3 (in inches)

= $2(8 \times 3 + 3 \times 3 + 3 \times 8) = 114 \: \rm in^2$

Thus, the amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

Learn more about surface area of cuboid here:

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5 0

2 years ago

If 7 key chains cost $55.65, then 12 key chains cost $

Nimfa-mama [501]

Divide $55.65 by 7 to get the cost of 1 key chain ($7.95). Then multiply the cost of 1 by 12 and get $95.40

3 0

3 years ago

Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all

posledela

This question is Incomplete

Complete Question

Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)

Answer:

0.7762

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Population mean = 6.20 bl/s

Standard deviation = 1.58 bl/s.

x = 5 bl/s

z = 5 - 6.20/1.58

z = -0.75949

The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)

Probability value from Z-Table:

P(x<5) = 0.22378

P(x>5) = 1 - P(x<5)

= 1 - 22378

= 0.77622

Approximately to 4 decimal places = 0.7762

The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762

5 0

3 years ago