Answer:
No
Step-by-step explanation:
To estimate population proportion from a sample, we must ensure that the sample data is random. Though a simple random sample of college students from a particular college was used as the sample data. However, selection of the college should have been randomized as well, a stratified random sample would have been a better sampling method whereby certain colleges are selected based on region or other criteria and then a random sample of it's statistics students selected. The sample proportion Obtian from a sample of this nature will be more representative of the population proportion of all college statistic student.
Let's factorise it :

![\: {\qquad \dashrightarrow \sf {x}^{3} (x + 3) + [-5(x + 3)] }](https://tex.z-dn.net/?f=%5C%3A%20%7B%5Cqquad%20%20%5Cdashrightarrow%20%5Csf%20%20%20%20%7Bx%7D%5E%7B3%7D%20%28x%20%2B%203%29%20%2B%20%5B-5%28x%20%2B%203%29%5D%20%20%7D)
Using Distributive property we get :



⠀
Therefore,

(1) For the parabola on the bottom row, the domain would be R and the range would be y ≥ -5
(2) For the hyperbola on the bottom row, the domain would be R\{3} (since there is an asymptote at x = 3) and the range would be R\{4} (since there is an asymptote at y = 4)
(3) For the square root function on the bottom row, the domain would be x ≥ -5 and the range would be (-∞, -2]
(4) For the function to the very right on the bottom row, the domain would be R and the range would be (-∞, -3]
Answer: 40
Step-by-step explanation:
* Hopefully the work below helps:) Mark me the brainliest:)!!
<em>∞ 234483279c20∞</em>
It would be 2/10, or 1/5, since two out of the 10 numbers are even. 2/10 simplifies to 1/5, since there is 1 for every 5 numbers.
We could turn this into a percentage by dividing 1 by 5, which gives us 0.2. Then we can multiply by 100 to get 20.
So, our probability of choosing an even number is:
2/10
OR
1/5
OR
20%
Hope I could help!