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Mashcka [7]
3 years ago
13

What is 2.6 as a fraction or mixed number? Pls help

Mathematics
2 answers:
WITCHER [35]3 years ago
8 0

Answer:

2\frac{3}{5}

Step-by-step explanation:

We need to write 2.6 as a fraction or a mixed number

2.6 or 2.6/1  are same

We have one number after the decimal point

To remove decimal point we multiply both top and bottom by 10

\frac{2.6}{1} =\frac{2.6*10}{1*10} = \frac{26}{10}

Now we divide it

             2           (quotient)

            ------------------------

    10      26

              20

            -------------------------  (subtract)

                  6       (remainder)

so mixed fraction is 2\frac{6}{10}

6/10 can be reduced to 3/5

So final answer is 2\frac{3}{5}

Alex73 [517]3 years ago
6 0
<span>The correct answer is 2 3/5.

Explanation:
2 is in the ones place and 6 is in the tenths place, which means we read this as "2 and 6 tenths". 6 tenths can also be written as 6/10, which makes this 2 6/10. This would then simplify to 2 3/5.</span>
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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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3 years ago
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What is 4log1/2^w(2log1/2^u-3log1/2^v written as a single logarithm?
IrinaK [193]
Given:

4log1/2^w (2log1/2^u-3log1/2^v)

Req'd:

Single logarithm = ?

Sol'n:

First remove the parenthesis,

4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)

Simplify each term,

Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:

 log 1/2 (w^4)  + 2 log 1/2 (u) - 3 log 1/2 (v) 
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)

We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):

Thus,

Log of 1/2 (w^4 u^2) - log of 1/2 (v^3) 

then use the quotient property of logarithms which is log of b (x)  - log of b (y) = log of b (x/y)

Therefore, 

log of 1/2 (w^4 u^2 / v^3)

and for the final step and answer, reorder or rearrange w^4 and u^2:

log of 1/2 (u^2 w^4 / v^3)  
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3 years ago
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melisa1 [442]
Answer- 16
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3 years ago
Given the functions f(x) = 2x -1 and g(x) =
Novosadov [1.4K]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

  • f(x) = 2x - 1
  • g(x) =  2 - x

a)

f(x) + g(x) = (2x - 1) + (2 - x)

                = 2x -1 + 2 - x

                = x + 1

b)

f(x) - g(x) = (2x - 1) - (2 - x)

              = 2x - 1 - 2 + x

               = 3x - 3

c)

g(-5) - f(-5)

Putting x = -5 in g(x) = 2 - x

g(x) = 2 - x

g(-5) = 2 - (-5) = 2+5 = 7

Putting x = -5 in f(x) = 2x - 1

f(x) = 2x - 1

f(-5) = 2(-5) - 1

       = -10 - 1

        = -11

Thus,

g(-5) - f(-5) = 7 - (-11) = 7+11 = 18

d)

f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2

e)

f(g(x)) = f(2-x)

          = 2(2-x)-1

          = 4-2x-1

          = 3-2x

6 0
3 years ago
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