According to the question, there are 37000 plants per hectare, the total corn plan required is 475,665.75 corn plants
<h3>Determining the area of a trapezium?</h3>
The trapezium is a 2 -dimensional plane shape with the area calculated as shown below:
The formula for calculating the area of a trapezoid is expressed as:
Area = 0.5(a + b)h
Given the following parameters
- a = 500 ft
b = 900ft
height h = 800ft
Substitute the given parameters
Area = 1/2 (500 + 900) * 800
Area = 1/2 (1400) * 800
Area = 560000 square feet
Since 1 acre is equivalent to 43560 square feet, hence the total acre required is expressed as:
Total acre = 560000/43560
Total acre = 12.856 acres
<h3>Convert the acres to total corn plant</h3>
Also since there are 37000 plants per hectare, the total corn plan required is 475,665.75 corn plants
Learn more on area of trapezoid here: brainly.com/question/1463152
Answer:
B
Step-by-step explanation:
To evaluate (f ￮ g)(- 4), first evaluate g(- 4) then substitute this value into f(x)
g(- 4) = 3(- 4) - 5 = - 12 - 5 = - 17, then
f(- 17) = 4(- 17) + 7 = - 68 + 7 = - 61 → B
Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
The answer is: " x = 0, 1 " .
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Explanation:
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Given:
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" √(x + 1) <span>− 1 = x " ; Solve for "x" ;
First, let us assume that "x </span>≥ -1 "
<span>
Add "1" to EACH SIDE of the equation:
</span>→ √(x + 1) − 1 + 1 = x + 1 ;
to get:
→ √(x + 1) = x + 1 .
Now, "square" EACH side of the equation:
→ [√(x + 1) ]² = (x + 1 )² ;
to get:
x + 1 = (x + 1)²
↔ (x + 1)² = (x + 1) .
Expand the "left-hand side" of the equation:
→ (x + 1)² = (x + 1)(x +1) ;
Note: (a+b)(c+d) = ac +ad + bc + bd ;
As such: (x + 1)(x + 1) = (x*x) + (x*1) +(1(x) + (1*1) ;
= x² + 1x + 1x + 1 ;
= x² + 2x + 1 ;
Now, substitute this "expanded" value, and bring down the "right-hand side" of the equation; and rewrite the equation:
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" (x + 1)² = (x + 1)(x +1) " ;
→ Rewrite as: " x² + 2x + 1 = x + 1 " ;
Subtract "x" ; and subtract "1" ; from EACH SIDE of the equation:
→ x² + 2x + 1 - x - 1 = x + 1 - x - 1 ;
to get: → x² <span>− x = 0
Factor out an "x" on the "left-hand side" of the equation:
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</span>x² − x = x(x − 1) ;
→ x (x − 1) = 0 ;
We have: "x" and "(x − 1)" ; when either of these two multiplicands are equal to zero, then the "right-hand side of the equation equals "zero" .
So, one value of "x" is "0" .
The other value for "x" ;
→ x − 1 = 0 ;
Add "1" to each side of the equation:
→ x − 1 + 1 = 0 + 1 ;
→ x = 1 ;
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So, the answers:
" x = 0, 1 " .
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