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3 years ago

Let f(x)=4x+7 and g(x)=3x-5. find (fog)(-4) A. -9 B. -61 C. -32 D. -17

Mathematics

1 answer:

vovikov84 [41]3 years ago

5 0

Answer:

Step-by-step explanation:

To evaluate (f ￮ g)(- 4), first evaluate g(- 4) then substitute this value into f(x)

g(- 4) = 3(- 4) - 5 = - 12 - 5 = - 17, then

f(- 17) = 4(- 17) + 7 = - 68 + 7 = - 61 → B

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Nataly [62]

Answer:

Step-by-step explanation:

To find s we use the cosine rule

That's

s² = SU² + ST² - 2(SU)(ST) cos S

From the question

SU = 5

ST = 13

S = 60°

Substituting the values into the expression we have

s² = 5² + 13² - 2(5)(13) cos 60

s² = 25 + 169 - 130cos 60

s² = 194 - 65

s² = 129

Find the square root of both sides

s= √129

s = 11.357816

We have the final answer as

<h3>s = 11.4 to the nearest tenth</h3>

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3 years ago

An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standa

Pepsi [2]

Answer:

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

M is the mean of five successive weightings (3.150)

ME is the margin of error from the mean

And margin of error (ME) can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)

s is the standard deviation of the random error (0.1)

N is the sample size (5)

Using the numbers 95% confidence interval estimate of the true weight is:

3.150± $\frac{2.776*0.1}{\sqrt{5} }$ ≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150± $\frac{4.604*0.1}{\sqrt{5} }$ ≈3.150±0.206

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3 years ago

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Sever21 [200]

No a repeating decimals have number repeating such as 555555.

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3 years ago

Determine f^-1(2) given the following: f(1 = -3f(2) = -2f(-1) = 2f(3) = -1

lana [24]

We assume that the function is as follows:

$f^{-1_{}}(2)=?$

Then, we have that:

$f^{-1}(x)=\frac{1}{f(x)}$

Thus, if we have that:

$f(2)=-2\Rightarrow f^{-1^{}_{}}(x)=\frac{1}{f(x)}\Rightarrow f^{-1}(2)=\frac{1}{f(2)}=\frac{1}{-2}\Rightarrow f^{-1}(2)=-\frac{1}{2}$

Therefore, the value for the function is f^-1(2) = -1/2 or

$f^{-1}(2)=-\frac{1}{2}$

8 0

1 year ago

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

on edg

5 0

4 years ago

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