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Yanka [14]
3 years ago
8

Triangle J K L is shown. Angle K L J is a right angle. The length of hypotenuse K J is 10.9 centimeters and the length of L J is

8.9 centimeters. Angle L K J is x.
Which equation can be used to find the measure of angle LKJ?

cos−1(StartFraction 8.9 Over 10.9 EndFraction) = x
cos−1(StartFraction 10.9 Over 8.9 EndFraction) = x
sin−1(StartFraction 10.9 Over 8.9 EndFraction) = x
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Mathematics
2 answers:
vazorg [7]3 years ago
8 0

Answer:

d

Step-by-step explanation:

edge2020-2021

scZoUnD [109]3 years ago
7 0

Answer:

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

Step-by-step explanation:

From the given triangle JKL;

Hypotenuse KJ = 10.9

Length LJ is the opposite = 8.9cm

The angle LKJ is the angle opposite to side KJ = x

Using the SOH CAH TOA Identity;

sin theta = opp/hyp

sin LKJ = LJ/KJ

Sinx = 8.9/10.9

x = arcsin(8.9/10.9)

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

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ASAP need help with system of equations... I'm too small brain to do it.
navik [9.2K]

Answer:

(x=0, y=11)

(x=2, y=9)

Step-by-step explanation:

first equation substitution for x first.

y=11-x

plug into 2nd equation

(x+2)^2+(11-x-7)^2=20

this should lead you into a quadratics equation.

you get x=0, x=2.

do the same for y value this time, subbing in the x value

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4 0
3 years ago
For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

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Answer:

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Step-by-step explanation:

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