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3 years ago

The numbers 22 and 35 are relatively prime. TrueFalse

Mathematics

2 answers:

aliina [53]3 years ago

8 0

Answer: True

Step-by-step explanation:

Ipatiy [6.2K]3 years ago

8 0

Answer:

<h3>False </h3><h3>They are coprime numbers </h3>

Step-by-step explanation:

<h3>I hope it helps ❤❤</h3>

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How many different ways can you solve a quadratic equation ? List them.

Semmy [17]

There are three basic methods for solving quadratic equations: factoring, using the quadratic formula, and completing the square.

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3 years ago

Partial fraction decomposition<br> 20x+9/25x^2+20x+4

ozzi

Step-by-step explanation:

We have

$\frac{20x + 9}{25 {x}^{2} + 20x + 4 }$

Let's factor the denomiator first,

the denomaitor is a perfect square so we get

$\frac{20x + 9}{(5x + 2) {}^{2} }$

Now, we must think of two fractions that

$\frac{a}{(5x + 2) {}^{2} } + \frac{b}{5x + 2}$

We use a perfect square term for one fraction, then a linear one for the next, because if we set both of the denomiator to the same factor, we would get a inconsistent system.

So right now, we have

$\frac{a}{(5x + 2) { }^{2} } + \frac{b}{5x + 2} = \frac{20x +9 }{25 {x}^{2} + 20x + 4 }$

$a + (5x + 2)b = 20x + 9$

$5b (x)= 20$

$a + 2b = 9$

$b = 4$

so that means that a is

$a + (2)(4) = 9$

$a + 8 = 9$

$a = 1$

So our equation is

$\frac{1}{(5x + 2) {}^{2} } + \frac{4}{5x + 2}$

6 0

2 years ago

25000000 in standard form

Elan Coil [88]

Answer:

2,500,000 This is in standard form.

2.5 x 10^6 This is in scientific notation.

Step-by-step explanation:

6 0

3 years ago

Triangle formula of a trianlge

adelina 88 [10]

Answer:

Formula for a triangle is 1/2bh

Step-by-step explanation:

B is for base and h is for height

5 0

2 years ago

Read 2 more answers

ASAP! I really need help with this question! No nonsense answers, and please attach the solution.

uysha [10]

Answer:

$\boxed{\sf Option \ 4}$

Step-by-step explanation:

$\sqrt{2x-3} +x=3$

Subtract x from both sides.

$\sqrt{2x-3} +x-x=-x+3$

$\sqrt{2x-3}=-x+3$

Square both sides.

$( \sqrt{2x-3})^2 =(-x+3)^2$

$2x-3=x^2-6x+9$

Subtract x²-6x+9 from both sides.

$2x-3-(x^2-6x+9 )=x^2-6x+9-(x^2-6x+9)$

$-x^2 +8x-12=0$

Factor left side of the equation.

$(-x+2)(x-6)=0$

Set factors equal to 0.

$-x+2=0\\-x=-2\\x=2$

$x-6=0\\x=6$

Check if the solutions are extraneous or not.

Plug x as 2.

$\sqrt{2(2)-3} +2=3\\ \sqrt{4-3} +2=3\\\sqrt{1} +2=3\\3=3$

x = 2 works in the equation.

Plug x as 6.

$\sqrt{2(6)-3} +6=3\\ \sqrt{12-3} +6=3\\\sqrt{9} +6=3\\3+6=3\\9=3$

x = 6 does not work in the equation.

5 0

3 years ago

Read 2 more answers