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Oduvanchick [21]
3 years ago
9

Find the inverse of the matrix, if it exists (Picture provided)

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

B. \left[\begin{array}{cc}\frac{9}{61} &\frac{2}{61} \\\frac{10}{61} &\frac{9}{61} \end{array}\right]

Step-by-step explanation:

The given matrix is

\left[\begin{array}{cc}9&-2\\-10&9\end{array}\right]

The determinant of this matrix is

=9\times9--10\times-2=61

Since the determinant is not zero, it means the inverse exists.

The inverse is given by

\frac{1}{determinant}\left[\begin{array}{cc}9&--2\\--10&9\end{array}\right]

\frac{1}{61}\left[\begin{array}{cc}9&2\\10&9\end{array}\right]

\left[\begin{array}{cc}\frac{9}{61} &\frac{2}{61} \\\frac{10}{61} &\frac{9}{61} \end{array}\right]

The correct choice is B.

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Neko [114]

Answer:

105/330 = 21/66 = 7/22

7/22 is the answer I think

Step-by-step explanation:

n(U) = 330

n(A) = 85

n(B) = 200

n(A n B) = 60

Now,

n(A U B) = n(A) + n(B) - n(A n B)

or, n(A U B) = 85 + 200 - 60

or, n(A U B) = 285 - 60 = 225

Now,

n(A U B) compliment = n(U) - n(A U B)

n(A U B) compliment = 330 - 225

so, n(A U B) compliment = 105

Now,

probability = 105/330

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A bank loaned out 16,000 ​$​, part of it at the rate of 6% per year and the rest at 14% per year. If the interest received in on
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Answer:

This question requires a comparison between two different variables 6% and 16% values.  If we let x=$ loaned on 6% loans and y=$ loaned on 16% loans, then we can relate two equations.

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Step-by-step explanation:

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Answer:

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An acrobat is on a platform that is 25 feet in the air. She jumps down in the initial velocity of 4 feet/seconds . Write the qua
Alenkasestr [34]

Answer:

a) h(t) = -16t²+ 4t + 25

b) Therefore it would take her 1.25 seconds to land safely in the net.

Step-by-step explanation:

The equation to be used is given as

h(t) = –gt²+ vt + S(t)

where g = force of gravity and because our question is in feet's = 16

V= Initial velocity

h = height

S = distance

a) The quadratic function for the above question

Using the formula

v = Initial velocity in the question = 4ft/s

S(t) = 25ft in the air

Hence the Quadratic function is

h(t) = –gt²+ vt + S(t)

h(t) = -16t²+ 4t + 25

b) If the safety net is placed 5 feet above the ground, how long will it take her to land safely in the net?

We are to find the time(t)

We can calculate this by using the quadratic function we derived in question (a)

The quadratic function is

h(t) = -16t²+ 4t + 25

Where, the height (h) = 5 feet above the ground

5= -16t² + 4t + 25

-16t² + 4t + 25 -5 = 0

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Using the quadratic equation formula of

x = -b ± √b² -4ac /2a

where the quadratic equation =

ax² + bx + c = 0

a = -16 , b = 4 , c = 20

x = -16 ± √4² - 4×-16×20 / 2×-16

x = -1 or ,1.25

Therefore it would take her 1.25 seconds to land safely in the net

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Answer:

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