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3 years ago

Solve each equation MUST SHOW WORK!!!! 10 points.

Mathematics

2 answers:

Sergio039 [100]3 years ago

4 0

Answer:

1. x=34

2. c=8

3. x=9

4. m=32

That the answer for all 4.

Step-by-step explanation: Hope this help :D

o-na [289]3 years ago

3 0

Answer:

x- 14= 20 answer x=34

c + 5=13 answer c=8

8x=72 answer x=9

m/4 = 8 answer m=32

Step-by-step explanation:

brainlest? please?

Let's solve your equation step-by-step.

x−14=20

Step 1: Add 14 to both sides.

x−14+14=20+14

x=34

______

Let's solve your equation step-by-step.

c+5=13

Step 1: Subtract 5 from both sides.

c+5−5=13−5

c = 8

_____

8x/8= 72/8

x= 9

____

m/4 • 4= 8 • 4

m = 32

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3 years ago

Read 2 more answers

Hom many times can the customer drive around the track for $8

wlad13 [49]

...more information is clearly needed

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3 years ago

3. In the figure below, find the values of x, y, and z.

Murrr4er [49]

Answer:

z= 13

x= 36

y= 18

Step-by-step explanation:

Solving for z.

We know that 108 degrees and (8z+4) are alternate exterior angles, so they are equal to each other.

We can set both of those angles equal to each other, and solve for our missing side, z.

108= 8z+4

104=8z

z= 13

Solving for x.

We know that 108 degrees and (3x) are alternate interior angles, so they would equal each other.

We can set both of these angles equal to each other, and solve for our missing side, x.

3x=108

x= 36

Solve for y.

We know that (4y) and (3x) are same side interior angles, so they would make 180 degrees. We know that (3x) would equal 108.

4y+108=180

4y= 72

y= 18

3 0

2 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago

I'LL MARK THE CORRECT ANSWER AS BRAINLIEST !!!<br> which one is true?

sergejj [24]

Answer:

2.7

Step-by-step explanation:

2.7×3 = 8.1

3x3=9

6×3= 18

18-8.1= 9.9 < 10

18-9= 9 < 10

18-18=0 < 10

5 0

3 years ago