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3 years ago

10

The test scores of 8 students are shown in the table above. Let m be the mean of the scores and M be the median of the score. Wh

at is the value of M-m?

1 answer:

MissTica3 years ago

5 0

Answer:

0

Step-by-step explanation:

Both M and m equal 81

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Help me out with this problem ?

3241004551 [841]

Answer:

(-4.5, 2.5)

Step-by-step explanation:

The solution for two graphed linear equations is the intersection (The point where two lines meet or cross).

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3 years ago

Solve for x please for 10 points

Ira Lisetskai [31]

Answer:

$\frac{x-2}{2+1}=\frac{4x-5}{3}$

$\frac{x-2}{3} =\frac{4x-5}{3}$

$3*\frac{x-2}{3} =\frac{4x-5}{3}*3$

$x-2=4x-5$

$x-2+5=4x-5+5$

$x-x+3=4x-x$

$3=3x$

$\frac{3}{3} =\frac{3x}{3}$

$1=x$

Step-by-step explanation:

your answer is B

7 0

3 years ago

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NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.

slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

$\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2$

<u>Total Surface Area</u>

Area of the isosceles triangle:

$\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2$

Total surface area:

$\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)$

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

$\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2$

<u>Total Surface Area</u>

Area of a pentagon:

$\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2$

where a is the side length.

Therefore:

$\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)$

Total surface area:

$\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)$

8 0

2 years ago

Which ordered pair is a solution of the inequality? 3y-6<12x

BartSMP [9]

The answer is 3. (4, -2)

7 0

3 years ago

8,326 x 9 =n<br>which is the answer?<br>A. 52,234<br>B.74,934<br>C.2,376<br>D.3008<br>E. none

Kazeer [188]

Answer:

B

Step-by-step explanation:

3 0

3 years ago

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