Answer:
this is my attachment answer!!
Step-by-step explanation:
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The value of the function f(x)=6/-2+2
at x=4 after rounded to the nearest tenth is -2.4.
Given Function of x : f(x)=6/-2+2
The given function showing the relationship between x and f(x) is f(x)=6/-2+2
where e is exponential and we have to find the value of f(4) by just putting the value of x=4 in the given function and round to the nearest tenth means replacing a number with an approximate value.
f(4)=6/-2+2
( The value of e is 2.7812)
f(4)=-3+2
f(4)=-3+2*0.30119 (The value of
is 0.30119)
f(4)=-3+0.60238
f(4)=-2.3972
Round -2.3972 to tenth is -2.4.
Hence the value of function of at x=4 is -2.4.
Learn more about function at brainly.com/question/10439235
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Answer: (175*π)yd^2
Step-by-step explanation:
If we find the total area enclosed by the outer circle, the subtract the area enclosed by the inner circle, the we inevitably get the area between the two regions.
The radius of the outer circle is 15yd + 5yd, which is 20yd. Use the formula for the area of a circle, A = pi*r^2. Therefore, the area enclosed by the outer circle is:

Now, the radius of the inner circle was stated to be 15yd. Do the same thing. Plug it into the formula:

Subtract the two areas to find the shaded blue area. Hopefully this was intuitive by thinking of area as an enclosed region of space.

Answer:
AB=13
Step-by-step explanation:
Given: BC= 14, AC=27
since AC is the whole line, you subtract by BC to solve AB so,
27-14=13
Answer:
D
Step-by-step explanation:
The answer is D because the question is asking for girls to boys. So anything that has 5 in it is wrong because it isn't asking for teachers, which eliminates A. So since it is asking <u>girls</u><u> </u><u>to</u><u> </u><u>boys</u> the number order has to be 48 then 41 because it is asking for girls first then to boys. So that makes B wrong. When it comes to the fraction part of the ratio the first number it is asking for (which is girls) <em><u>alwa</u><u>ys</u></em> goes on top. So that eliminates C which leaves only answer to be D.