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Leona [35]
3 years ago
11

Each side of an equilateral triangle measure 11 centimeters. To the nearest tenth of an centimeter, what is the length of the al

titude
Mathematics
1 answer:
Orlov [11]3 years ago
3 0
The length of the altitude is 9.5 cm.

The altitude bisects the base of the equilateral triangle (this is because the two sides emerging from the vertex are equal).  This gives us a right triangle with leg 5.5 and hypotenuse 11.  We use the Pythagorean theorem:

5.5² + h² = 11²
30.25 + h² = 121

Subtract 30.25 from both sides:
30.25 + h² - 30.25 = 121 - 30.25
h² = 90.75

Take the square root of both sides:
√h² = √90.75
h = 9.5
You might be interested in
Rectangle
eduard

Options A and D are correct. The pair of measurements that could be the dimensions of rectangle B is 6 cm by 1.5 cm and 18 cm by 4.5 cm.

For us to get a scale copy of the dimension, we need to first find the scale factor as shown;

Given the measure of rectangle A:

  • Length= 12cm
  • Width = 3cm

To get all of the measurement pairs that could be the dimensions of Rectangle  B, we need to multiply the length and width by the same factor

Multiplying by 1/2

New length = 12 × 0.5 = 6cm

New width = 3 × 0.5 = 1.5cm

Hence 6cm by 1.5cm can be dimension of B

Multiplying by 1.5

New length = 12 × 1.5 = 18cm

New width = 3 × 1.5 = 4.5cm

Hence 18cm by 4.5cm can be dimension of B

Learn more here: brainly.com/question/24759485

5 0
2 years ago
timur paid $4.50 to enter the fair. he then bought a pretzel for $1.50 and played a game $1. last he rode a roller coaster for $
Soloha48 [4]
X-(4.5+1.5+1+3)= 8
x-10=8
+10. +10
x= 18

He took $18 to the fair. You take his original amount and subtract the things he paid for/bought to get what he came home with. I hope it helps!
8 0
2 years ago
(HELP FINAL EXAM) If two states are selected at random from a group of 40 ​states, determine the number of possible outcomes if
Hitman42 [59]

Answer:

With replacement, there are 1600 possible outcomes.

Without replacement, there are 1560 possible outcomes.

Step-by-step explanation:

Chosen with replacement:

State is chosen, then put back in the group, then another state can be chosen. In both cases, there will be 40 possible outcomes, as the first taken state is placed back. So

40*40 = 1600

With replacement, there are 1600 possible outcomes.

Chosen without replacement:

State and chosen and is not replaced.

So, for the second state, there will be only 39 possible outcomes.

40*39 = 1560

Without replacement, there are 1560 possible outcomes.

7 0
2 years ago
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
2. Given square CANE with diagonals
svlad2 [7]
What’s something goes up but never comes down?
6 0
3 years ago
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