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3 years ago

IMPORTANT PLEASE!! 10 POINTS :)

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

5 0

Answer:

The domain is all the possible inputs for this function. The range is all the possible outputs for this function.

The line starts at the x-value of 0 and ends at the x-value of 12. Therefore, your domain is D: [0, 12].

The line starts at the y-value of 9000 and ends at the y-value of 0. Therefore, your range is R: [0, 9000].

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Felix found the sum of two prime numbers and one composite number to be 45. The difference between the greatest and least number

erica [24]

I think it could be 13,17, and 15.
If I am wrong then I am sorry

3 0

3 years ago

Three students performed a science experiment using salt and a beaker. The beaker contained 530.2 grams of salt before the exper

anzhelika [568]

We are subtracting 3 * 47.36 from 530.2

3 * 47.36 = 142.08

530.2 - 142.08 = 388.12

Your answer should be 388.12 grams left. Hope this helps!

3 0

3 years ago

Read 2 more answers

Since r is parallel to s, determine the measure x indicated in the figure below

Butoxors [25]

Answer:

x =s

Step-by-step explanation:

42 9 x 143 x r

3 0

2 years ago

What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form? x = –4 ± 2StartRoot 3 EndRoot x = –4

SCORPION-xisa [38]

Answer:

Step-by-step explanation:

Discriminant Δ = √(8²-4×(1)×(4)) = √(48) = √(4×12) = √(4)×√(12) = 2√(12)

then x = (-8 ± 2√(12))÷2 = -4 ±√(12) = -4 ±√(3×4) = -4 ± 2√(3)

4 0

3 years ago

Read 2 more answers

An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 3ft long with a diameter of 2.2 ft . S

Contact [7]

4 minutes 34 seconds will takes to empty the tank, if the starts completely full and oil drained at a rate of 2.5 $ft^{3}$ per minute.

Step-by-step explanation:

The given is,

Tank is shaped like a cylinder that is 3 ft long with a diameter of 2.2 ft.

Oil drained at a rate of 2.5 $ft^{3}$ per minute.

Step:1

Time taken to dry the oil tank is,

T = $\frac{Volume of oil}{Oil drain rate}$ ....................................(1)

Step:2

Volume of the oil is,

$V = \pi r^{2} h$ .................................................(2)

Where, r - Radius of Cylinder

$r = \frac{d}{2}$

$r = \frac{2.2}{2}$

r = 1.1 ft

From eqn (1),

V = $\pi$ × $1.1^{2}$ × 3

= 11.40398 $ft^{3}$

Step:3

From equation (1)

= $\frac{11.40398}{2.5}$

= 4.56

= 4.56 minutes

T = 4 minutes 34 seconds

Result:

Time taken to dry the oil tank is 4 minutes 34 seconds, if a cylinder is 3 ft long with a diameter of 2.2 ft and oil is drained at a rate of 2.5ft^3 per minute.

4 0

2 years ago